concrete pavement with a velocity of 17,15 m.s and it then bounces to a maximum height of 4 m A cricket ball, mass 156 g, is dropped from point A on a tall building, 15 m high. It strikes the m 15 m How long does it take the cricket ball to hit the pavement the first time? (3) If the effects of air friction are NOT ignored during the fall of the cricket ball, how is the value calculated in Question 3.1 influenced? Write down HIGHER, LOWER or STAYS THE SAME The cricket ball is in contact with the concrete pavement for 0,8 s. Ignore the effects of air friction. Take the DOWNWARD motion as POSITIVE (1) Calculate the impulse of the cricket ball on the pavement. Calculate the average (net) force exerted by the pavement on the cricket ball. Sketch the position time graph for the motion of the cricket ball from the moment it is dropped until it reaches its maximum height after the bounce. USE POINT A AS THE ZERO POSITION. Indicate the following on the graph: . . The height from which the cricket ball is dropped. The height reached by the cricket ball after the bounce. The time when the cricket ball leaves the pavement. (8) (4)