p - 997.903 kg / (Vg) (Vg) Now we may calculate the entire volume V using the plane's standard reserve buoyancy. Assuming the typical reserve buoyancy of 80%, width v 80% of the entire capacity will be above the water's surface. As a result, we have: Get 0.8Vgw equals 0.8Vg plus Vgw where w denotes the water's density. By solving lane's total volum able total mass of for, we obtain: (volume above p = (0.8pw)/(1-08) (1-0.8) When we enter the value of into the initial y to that of other f the water in the equation, we obtain: wance is 12.0 kg g/m. (4 marks) 997.903 kg divided by (0.197Vg) (0.8w)/(1-0.8) ctly into the wind. yields 997.903 kg (0.197Vg) Fremantle, what is what is the total If we simplify, we get: p = 1091.27 kg/m3 Hence, the seaplane has a density of 1091.27 kg/m3