Question
P1 (20 points) Implement a binary search of an array iteratively using the method public static
P1 (20 points)
Implement a binary search of an array iteratively using the method
public static
P2 (30 points)
Consider an array data of n numerical values in sorted order and a list of numerical target values (target values are not necessarily sorted). Your goal is to compute the smallest range of array indices that contains all of the target values. If a target value is smaller than data[0], the range should start with -1. If a target value is larger than data[n - 1], the range should end with n.
For example, given the array [ 5 8 10 13 15 20 22 26] and the target values (8, 2, 9, 17), the range is -1 to 5.
Devise an efficient algorithm that solves this problem and implement it in
public static
Interval findInterval(T[] sortedData, List
where Interval is a class that provides two public methods getLower() and getUpper() to return the lower and upper values of an Interval object. Implement the Interval class.
If you have n data values in the array and m target values in the list, what is the Big Oh performance of your algorithm?
ArraySearcher.java
/** A class of static methods for searching an array of Comparable objects. */ public class ArraySearcher { // Segment 18.3 /** Searches an unsorted array for anEntry. */ public static boolean inArrayIterativeUnsorted(T[] anArray, T anEntry) { boolean found = false; int index = 0; while (!found && (index < anArray.length)) { if (anEntry.equals(anArray[index])) found = true; index++; } // end while return found; } // end inArrayIterativeUnsorted // ======================================================================================== // Segment 18.6 /** Searches an unsorted array for anEntry. */ public static boolean inArrayRecursiveUnsorted(T[] anArray, T anEntry) { return search(anArray, 0, anArray.length - 1, anEntry); } // end inArrayRecursiveUnsorted // Searches anArray[first] through anArray[last] for desiredItem. // first >= 0 and < anArray.length. // last >= 0 and < anArray.length. private static boolean search(T[] anArray, int first, int last, T desiredItem) { boolean found = false; if (first > last) found = false; // No elements to search else if (desiredItem.equals(anArray[first])) found = true; else found = search(anArray, first + 1, last, desiredItem); return found; } // end search // ========================================================================================
/** Searches a sorted array for anEntry. */ public static > boolean inArrayRecursiveSorted(T[] anArray, T anEntry) { return binarySearch(anArray, 0, anArray.length - 1, anEntry); } // end inArrayRecursiveSorted // Segment 18.13 // Searches anArray[first] through anArray[last] for desiredItem. // first >= 0 and < anArray.length. // last >= 0 and < anArray.length. private static > boolean binarySearch(T[] anArray, int first, int last, T desiredItem) { boolean found; int mid = first + (last - first) / 2; if (first > last) found = false; else if (desiredItem.equals(anArray[mid])) found = true; else if (desiredItem.compareTo(anArray[mid]) < 0) found = binarySearch(anArray, first, mid - 1, desiredItem); else found = binarySearch(anArray, mid + 1, last, desiredItem); return found; } // end binarySearch // ========================================================================================
public static void display(T[] anArray) { System.out.print("The array contains the following entries: "); for (int index = 0; index < anArray.length; index++) { System.out.print(anArray[index] + " "); } // end for System.out.println(); } // end display } // end ArraySearcher
ArraySort.java
import java.util.* ; public class SortArray { public static
public static
public static
public static
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