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P6.38 If the reaction Fe2N(s)+3/2H2(g)2Fe(s)+NH3(g) comes to equilibrium at a total pressure of 1 bar, analysis of the gas shows that at 700 . and
P6.38 If the reaction Fe2N(s)+3/2H2(g)2Fe(s)+NH3(g) comes to equilibrium at a total pressure of 1 bar, analysis of the gas shows that at 700 . and 800.K,PNH3/PH2=1.971 and 0.9780, respectively, if only H2(g) was initially present in the gas phase and Fe2N(s) was in excess. a. Calculate KP at 700 . and 800 . K. b. Calculate rSat 700.K and 800.K and rH, assuming that it is independent of temperature. c. Calculate rG for this reaction at 298.15K
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