Question
P(A)=0.7, P(B)=0.56 and P(B|A)=0.75. Find the probability of not a and not b. P(not a and not b). The answer of the textbook shows that
P(A)=0.7, P(B)=0.56 and P(B|A)=0.75. Find the probability of not a and not b. P(not a and not b).
The answer of the textbook shows that (1-(0.7+0.56-0.7*0.75)=0.265. I can't understand it. Plz, explain the step. Thank you.
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How To Prove It A Structured Approach
Authors: Daniel J Velleman
2nd Edition
0511159439, 9780511159435
