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part 1 3. Explain any difference in the values before and after the collision. The system lost 0.02 kg m/s of momentum. Therefore, by these
part 1
3. Explain any difference in the values before and after the collision. The system lost 0.02 kg m/s of momentum. Therefore, by these values' momentum was not conserved since the system momentum before the collision is not the same as after the collision. We can account for the difference in the values before and after the collision by realizing that in this experiment it is very difficult to accurately measure time.3. Explain any difference in the values before and after the collision. In this elastic collision experiment. two objects came together. collided. and then moyed apart again but instead of there being no loss of kinetic energy as there should be, we encountered a kinetic loss of 0.02 kgmfs or 2.? percent difference. For a collision to be totally elastic there must be no loss of kinetic energy. We can assume that the loss of kinetic energy is due to human error in timing each eyent. 3. Explain any difference in the values before and after the collision. In this elastic collision experiment, two objects came together, collided, and then moved apart again but instead of there being no loss of kinetic energy as there should be, we encountered a kinetic loss of .12 kg m/s or 2.7 percent difference. For a collision to be totally elastic there must be no loss of kinetic energy. We can assume that the loss of kinetic energy is due to human error in timing each event. Both the momentum and kinetic energy should have been conserved.1. The law of conservation of momentum states that the total momentum before a collision equals the total momentum after a collision provided there are no outside forces acting on the objects in the system. What outside forces are acting on the present system that could affect the results of the experiments? There are multiple factors which could affect the results of the experiment. J The first being human error. It is rather difficult to get the exact time recorde for each event this in turn affects the calculation for the velocity,r of the object. There could have also been an issue with the setup {the angle} of the board. There could also be issues with the levelness of the flat surface in this case a floor and issues with friction. 2. l|l'iil'hat did you observe when Cart A containing added mass collided with lCart B containing no mass? How does the law of conservation of momentum explain this collision? I observed that the increased mass connected to an increase in momentum of Cart A which then collided with Cart B (which was at rest and contained no washers) with Cart B absorbing the force of the impact and transferring it into kinetic energy. 3. In one of the experiments, Cart A may reverse direction after the collision. How is this accounted for in your calculations? Cart A did reverse direction after it collided with Cart B . This was a reverse in1 direction and therefore was represented by a negative sign, which implies that the Cart A changed directionStep by Step Solution
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