Part 2: m = 4 Compute the equation of the line tangles to y = x - 4 and (2, 0). Use the point-slope form: y = yitm(x -x1) Put your answer in simplified, slope-intercept form. yLet f(x) = 23 - x2 The slope of the tangent line to the graph of f( ) at the point (-4, 7) is 256 The equation of the tangent line to the graph of f(x) at (-4, 7) is y = max + b for and 256Let f(x) = x2 - 7x. (A) Find the slope of the secant line joining (2, f(2) ) and (9, f(9)). Slope of secant line = 4 (B) Find the slope of the secant line joining (6, f(6) ) and (6 + h, f(6 + h)). Slope of secant line = -6 (C) Find the slope of the tangent line at (6, f(6)). Slope of tangent line = (D) Find the equation of the tangent line at (6, f(6)). = 8x + 39