Part 3: Varying the Miss Create a table in your notebook like the one in Part 1, but for only three trials Mensure for three trials, sing the same and for each trial but a different M. Analysis Part 1 Equation (1) can be written in the form 97479 0.00606072 4.12.2008 (2) PM Thus we expect that a graph of r . T should be a straight line y -az with a slope a- Let to check this Make a graph of your data from Part 1 with on the vertical noxis and on the horizontal Find the line of best fit to your daim determine the slope a. Find the fractional difference between this value of a measured off your graph and the quantity (s. Part 2 Equation (1) can be rewritten in the form F = 42 (3) Thus we expect that a graph of Fu, 1/T should be a straight line you with a slope = (4MP). Let us check this Make a graph of your data from Part 2 with on the vertical axis and 1/7 on the horizontal Find the line of best fit to your data and determine the slope . Find the fractional difference between this value of a measured off your graph and the quantity (4Mr). Part 3 With only three data points a graph is not really useful. Instead, for each of your three trials, use M., T and equation (1) to calculate what we would expect to beFor each of these three theoretical predictions, find the fractional difference from the actual measured value Fe = mg Tz r lm E = mg 1478 27= 2 4te mr using Equation (1) which is fc Senecal procedure pick moss pick radios R Hang mass from side post, Pick to E ilk) 0.2 sec. 10.14190 15.6 0.1 sec 0.14 3 14.5 4. 208 13.10 0.3 see 5 208 1). FC = mg = (2) -794: 1 2-10- wo 0.15 see 1.5 peu 0./47 3 Per 0.779 24 + 50 208 258 355 11-25 4 Star 20 WY 0-0 201 Trial mass (29) 1 208 kg Zof ES 2 150 2.1 isel 001S1x94 rcm) Fc= mg Tis) 2013 0 14798 2.7725 5 13 o 19698 12.0:43 0175 507 kg: 0.050 73. - 10 1 *4.5 0.49 2.382 S 17.74 1.7845 x 13 799:0-13 16:42:31.6475) Revolations 10 + mass 3 Zou Gle 208 kg 208 m mass hange Fo rcm) T75) 12.53-10- 1.253 19.50 1.980 Trial mass 1 156 2 104 3 208 4 0.49 13 13 13 0.49 0.49 20.20 10. Tzu 13 5 13 208-52= 15h - 104 = 104 200 Part 3: Varying the Miss Create a table in your notebook like the one in Part 1, but for only three trials Mensure for three trials, sing the same and for each trial but a different M. Analysis Part 1 Equation (1) can be written in the form 97479 0.00606072 4.12.2008 (2) PM Thus we expect that a graph of r . T should be a straight line y -az with a slope a- Let to check this Make a graph of your data from Part 1 with on the vertical noxis and on the horizontal Find the line of best fit to your daim determine the slope a. Find the fractional difference between this value of a measured off your graph and the quantity (s. Part 2 Equation (1) can be rewritten in the form F = 42 (3) Thus we expect that a graph of Fu, 1/T should be a straight line you with a slope = (4MP). Let us check this Make a graph of your data from Part 2 with on the vertical axis and 1/7 on the horizontal Find the line of best fit to your data and determine the slope . Find the fractional difference between this value of a measured off your graph and the quantity (4Mr). Part 3 With only three data points a graph is not really useful. Instead, for each of your three trials, use M., T and equation (1) to calculate what we would expect to beFor each of these three theoretical predictions, find the fractional difference from the actual measured value Fe = mg Tz r lm E = mg 1478 27= 2 4te mr using Equation (1) which is fc Senecal procedure pick moss pick radios R Hang mass from side post, Pick to E ilk) 0.2 sec. 10.14190 15.6 0.1 sec 0.14 3 14.5 4. 208 13.10 0.3 see 5 208 1). FC = mg = (2) -794: 1 2-10- wo 0.15 see 1.5 peu 0./47 3 Per 0.779 24 + 50 208 258 355 11-25 4 Star 20 WY 0-0 201 Trial mass (29) 1 208 kg Zof ES 2 150 2.1 isel 001S1x94 rcm) Fc= mg Tis) 2013 0 14798 2.7725 5 13 o 19698 12.0:43 0175 507 kg: 0.050 73. - 10 1 *4.5 0.49 2.382 S 17.74 1.7845 x 13 799:0-13 16:42:31.6475) Revolations 10 + mass 3 Zou Gle 208 kg 208 m mass hange Fo rcm) T75) 12.53-10- 1.253 19.50 1.980 Trial mass 1 156 2 104 3 208 4 0.49 13 13 13 0.49 0.49 20.20 10. Tzu 13 5 13 208-52= 15h - 104 = 104 200