Part A At what two times is the baseball at a height of 11.0 m above the point at which it left the bat? Express your answers in seconds. Enter your answers in ascending order separated by a comma. IVO AEQ ? t1, t2 = Submit Request Answer Part B Calculate the horizontal component of the baseball's velocity at an earlier time calculated in part A. Express your answer in meters per second. ? m/s Submit Request AnswerPart C Calculate the vertical component of the baseball's velocity at an earlier time calculated in part A. Express your answer in meters per second. VO AEQ ? m/s Submit Request Answer Part D Calculate the horizontal component of the baseball's velocity at a later time calculated in part A. Express your answer in meters per second. AEd ? m/s Submit Request AnswerPart E Calculate the vertical component of the baseball's velocity at a later time calculated in part A. Express your answer in meters per second. AEQ ? UJ = m/s Submit Request Answer Part F What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat? Express your answer in meters per second. AEQ ? U = m/s Submit Request AnswerPart G What is the direction of the baseball's velocity when it returns to the level at which it left the bat? Express your answer in degrees. VO AE ? 0 = " below the horizontal Submit Request AnswerA major leaguer hits a baseball so that it leaves the bat at a speed of 32.8 mfg and at an angle of 38.20 above the horizontal. You can ignore air resistance. For related problemsolving tips and strategies. you may want to View a Video Tutor Solution of ght and range of a projectile i: a batted baseball