Question
Part A: If 44.9mL of lead() nitrate solution reacts completely with excess sodium iodide solution to yield 0.712g of precipitate, what is the molarity of
Part A:
If 44.9mL of lead() nitrate solution reacts completely with excess sodium iodide solution to yield 0.712g of precipitate, what is the molarity of lead() ion in the original solution? Round your answer to 3 significant figures.
Part B:
How many grams of solid barium sulfate form when 74.0mL of 0.760M barium chloride reacts with 98.0mL
of 0.480 M sodium sulfate? Aqueous sodium chloride also forms in this reaction. Round your answer to 3 significant figures.
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Statistical Reasoning for Everyday Life
Authors: Jeff Bennett, Bill Briggs, Mario F. Triola
4th edition
978-0321817747, 321817745, 978-0321890139, 321890132, 321817621, 978-0321817624
