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Part A: If 44.9mL of lead() nitrate solution reacts completely with excess sodium iodide solution to yield 0.712g of precipitate, what is the molarity of

Part A:

If 44.9mL of lead() nitrate solution reacts completely with excess sodium iodide solution to yield 0.712g of precipitate, what is the molarity of lead() ion in the original solution? Round your answer to 3 significant figures.

Part B:

How many grams of solid barium sulfate form when 74.0mL of 0.760M barium chloride reacts with 98.0mL

of 0.480 M sodium sulfate? Aqueous sodium chloride also forms in this reaction. Round your answer to 3 significant figures.

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