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Part A Part B The ionization constant of water is O [H*](OH-] = 10-14 O [H+]2 = 14 O (OH)]2 = 14 O [H2O](OH) =

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The ionization constant of water is O [H*](OH-] = 10-14 O [H+]2 = 14 O (OH)]2 = 14 O [H2O](OH) = 1 What is the correct expression for the solubility product constant of CaF2? (CaF2 H Ca2+ + 2F") O [OH] [F]2 = [H] [Ca?) o [Ca2+] [F]? = Ksp (Ca2] x 2[F] - Ksp O [Ca] [F12 /H20 - Ksp

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