Part A

The de Broglie wavelength of an electron with a velocity of $690{10}^6\frac{m}{s}$ is m$.$ The mass of the electron is $9\mathrm{.}11{10}^{-28}g.$

$1\mathrm{.}05{10}^{-16}$

$9\mathrm{.}49{10}^{12}$

$9\mathrm{.}49{10}^9$

$1\mathrm{.}05{10}^{-10}$

$105{10}^{-13}$