Part A - The normal force F'N : its magnitude is NOT automatically known. (A common mistake is to think FN is always equal to the magnitude of the weight.) Learning Goal: Application of Newton's Laws Here we use a space holder for magnitude FN. Which of the following is the correct way to write its x- and y- components of FN? It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) Keep 2 digits after the decimal point. Unit is Newtons. Separate answers by commas. W. = W. = O FN, X = 0 FN, y= - FN IF, = F.. +W. EF, = Fx, +W, 2nd law EF, = ma, EF, = ma, O FN, X = FNCOS330 FN, y= FN Sin330 It 330 O FN, X = FNSin330 FN, y= FN COS330 OFN, X = 0 FN, y = FN A block slides down a smooth incline (without friction) which makes 330 relative to the horizontal.. (We will OFN , X = FN , FN, y = 0 evisit this problem and include friction). The block's mass is m = 27.0 kg , The magnitude of the gravitational acceleration is 9.80 m/s2 Submit Request Answer Part B - Remember: weight is a force, which is a vector. Calculate its x- and y- components. Pay attention to the geometry, and what angle to use, which trignometrical functions to use, and the signs of the components. Keep 2 digits after the decimal point. Unit is Newtons. Separate answers by commas. FOE ? weight vector WI, Wy = Submit Request Answer Now the table on the right side of the figure is complete with FN as a space holder. You can write up EF, and EFy, with FN as a space holder. You will apply Newton's Laws (1st or 2nd). Part C - The physical situation is that the block slides down the incline (along the x axis). You can find the magnitude of FN. If you don't know how, open the "hints". View Available Hint(s) boo ? magnitude FN Submit Part D - Now apply Newton's 2nd Law in the x- axis to the find the block's acceleration ax down the inlcine. Keep 3 digits after the decimal point. Unit is m/s2 m/ $2 Submit Request