Part AFind the energy U1 of the dielectric filled capacitor U1=_______JPart BThe dielectric plate is now slowly pulled out of the capacitor which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half filled with the dielectric U2=______JPart CThe capacitor is now disconnected from the battery and the dielectric plate is slowly removed the rest of the capacitor. Find the new energy of the capacitor,U3.U3=_______JPart D I'm the process of removing the remaining portion of of the dielectric from the disconnected capacitor,how much work W is done by the external agent acting on the dielectric?W=_______J

+ Energy of a Capacitor in the Presence of a Dielectric A dielectric-filled parallel-plate capacitor has plate area A = 10,0 cm plate separation d = 9.00 mm and dielectric constant