Part one Questions 1 - 2? Part 2 Questions 1 - 3?
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 23.6 with a standard deviation of 3.9, while the 200 students in group 2 had a mean score of 17.7 with a standard deviation of 3. Complete parts (a) and (b) below. (a) Determine the 90% confidence interval for the difference in scores, H, - 2. Interpret the interval. The lower bound is The upper bound is (Round to three decimal places as needed.) Interpret the interval. Choose the correct answer below. A. There is a 90% probability that the difference of the means is in the interval. "B. The researchers are 90% confident that the difference of the means is in the interval. OC. The researchers are 90% confident that the difference between randomly selected individuals will be in the interval. D. There is a 90% probability that the difference between randomly selected individuals will be in the interval. (b) What does this say about priming? A. Since the 90% confidence interval contains zero, the results suggest that priming does have an effect on scores. B. Since the 90% confidence interval contains zero, the results suggest that priming does not have an effect on scores. C. Since the 90% confidence interval does not contain zero, the results suggest that priming does have an effect on scores. Question 1 OD. Since the 90% confidence interval does not contain zero, the results suggest that priming does not have an effect on scores. A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.61 hours, with a standard deviation of 2.37 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4:45 hours, with a standard deviation of 1.98 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (H, - H2) Let u, represent the mean leisure hours of adults with no children under the age of 18 and #2 represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for ( H1 - H2) is the range from | hours to hours. (Round to two decimal places as needed.) What is the interpretation of this confidence interval? Question 2 O A. There is 90% confidence that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. B. There is a 90% probability that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. C. There is 90% confidence that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. OD. There is a 90% probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. A physical therapist wanted to know whether the mean step pulse of men was less than the mean Two sample T for Men vs Women step pulse of women. She randomly selected 55 men and 77 women to participate in the study. Mean StDev SE Mean Each subject was required to step up and down a 6-inch platform. The pulse of each subject was Men 55 112.7 11.9 1.6 then recorded. The following results were obtained. Women 118 7 -14.3 99% Cl for mu Men - mu Women (- 12.04, 0.04) T-Test mu Men = mu Women (vs
