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Pb(NO3)2 + 2 NaBr - PbBr2 + 2 NaNO How many moles of Sodium bromide will be needed in order to react with 4.44 moles

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Pb(NO3)2 + 2 NaBr - PbBr2 + 2 NaNO How many moles of Sodium bromide will be needed in order to react with 4.44 moles of Lead (II) nitrate ? O 2.22 moles O 8.88 moles O 2.00 moles O 1.00 moles

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