Perfect gas follows egn. Cy.m=a+bT, (b=0.09 Jmol '2; a=13 Jmol-'-). And suppose 6.00 mole of this gas go from 700 K and 2.5 atm to 200 K and 5.5 atm. Calculate 1. Heat (9) 2. Work (w) joule 3. AU (KJ). During a reversible constant pressure non-flow process at P=2.8 bar, the system process changed from V1=0.40 m3/kg, T1=40 C to V2=0.71 m3/kg, T2=280 C. Where specific heat of the fluid is shown below where T is in C. 30 Cp=(2.7 + kJ/kg C (T +15) Calculate: (1) Heat added/kg; (KI/kg) (i) Work done/kg (KJ/kg) (iii) Change in internal energy/kg (KJ/kg), (iv) Change in enthalpy/kg (KJ/kg)