pH Worksheet to Accompany Experiment $10$

To find pH:

$pH=-log[H_3{O}^{+}]$therefore if $[H^{+}]=1{10}^{-7}$ the $pH=7\mathrm{.}0$

if $[H^{+}]=2{10}^{-7}$ the $pH=6\mathrm{.}7$

steps on my calculat

To find $H^{+}$or $H_3{O}^{+}$

antilog$(-pH$

therefore if $pH=4\mathrm{.}0[H^{+}]=1{10}^{-4}$

$[H_3{O}^{+}]={10}^{{?}^{{?}^{?}}}-pH$

if $pH=4\mathrm{.}8[H^{+}]=1\mathrm{.}6{10}^{-5}$

steps on my calculator :

To convert between $pH$ and $O{H}^{-}($in the same solution$)$

$[H_3{O}^{+}][O{H}^{-}]=1\mathrm{.}00{10}^{-14}$

Problems:

Complete each row in the table below by using one of the $3$ equations listed above.

$\backslash$table$[[H_{+}$or $H_{3}O+,O{H}^{-},pH$