Physics

Note : It already has answers key, only need the solution for those answers.

Solutions for task 1, 2 and 4 only cause I already have the solution of task 3

Topic : Problem Solving Involving Properties of Light

Answers key

Name of Learner: Grade and Section: Date: olution Given: Mit= 40 cm GENERAL PHYSICS 2 ACTIVITY SHEET Asked : 01 =? Problem-Solving Involving Properties of Light Process: Things to consid The angle Learning Competency with Code 0, (Law of reflect The leng Solve problems involving reflection, refraction, dispersion, and polarization in contexts such The angl as, but not limited to, (polarizing) sunglasses, atmospheric haloes, and rainbows. combined, the ang! (STEM_GP120PTIVc-21) 4. When th the same Background Information for Learners Extracting the EM waves exhibit properties like reflection, refraction, dispersion and trigonometric funct polarization. Reflection is a property of EM wave that allows it to bounce back upon hitting a smooth surface. If it is a regular kind of reflection, the angle of incidence is equal to the angle of reflection. This phenomenon could be observed on cases like those of mirrors or other smooth surfaces. The refraction of EM waves usually takes place when it crosses one medium to another, specifically between mediums of varying refractive index. In the case of refraction, the Snell's law is usually considered to describe the change in the speed and direction of an EM wave. The A To determin dispersion of light and the polarization are also properties exhibited by EM waves. Using On problems related to the polarization the Malus Law is usually employed to solve aimed at this ar various problems involving intensity and angles pertaining to axis of transmission. Task No. 1: III. Activity Proper Directions: Sol and the unknow Consider two Sample Problem on Reflection incident light ra angle of incider Consider two plane mirrors M, and M2 arranged perpendicular to one the 12 cm leng another. An incident light ray strikes the first mirror at its middle point 20 cm from the intersection. At what angle of incidence should the first ray be set to produce a reflected ray that will hit the middle point of the second mirror? Inc Normal Incident Ray 0 1 =? 0 , =? M2- length=30 B = ? M1 - length=40cmSolution Given: Mij= 40 cm Miz= 30 c Asked : 0; =? Process: Things to consider: The angle of incidence 0, is equal to the angle of reflection 0, (Law of reflection). The length considered are all 12 of both mirror's lengths. ontexts such The angle & could be the key in determining the the O, since when IS. combined, the angle may sum up to 90 . When the angle of reflection is determined the angle of incidence will be the same Extracting the available information from the problem you can employ a trigonometric function to determine B using the formula of Tangent. back upon cidence is 15 cm tang = 15em cases like 20 cmi ; tanB = 0.75 sually takes iums of B = tan -10.75 = 36.87 20 cm vave. The A To determine the 0, = 90 - 36.870 = 53.130 A waves. Using The Law of Reflection: 0, = 0, = 53. 13' The incident ray should be d to solve aimed at this angle. mission. Task No. 1: Problem Solving (reflection) Directions: Solve the problem below in your answer sheet. Identify the given data and the unknown. Consider two plane mirrors M, and M2 arranged perpendicular to one another. An incident light ray strikes the first mirror at 15 cm from the intersection O. At what angle of incidence should the first ray be set to produce a reflected ray that will hit the 12 cm length of the second mirror from point O? ne n from the Normal ce a Incident Ray 01 =7 0, =7 12 cm \\B = ? - length=30 M1 15.0 cmSample Problem on Refraction Task No. 2: Proble A light ray coming from air penetrates an unknown material at an angle of incidence equal to 550 with respect to the normal. The air has a refractive index of Directions: Solve t 1.0 and the unknown material causes the light ray to bend at 450 with the normal. and the unknown. How fast will the light moves on this material? A light ray com incidence equal to 1.0 and the unknow Normal How fast will the li 0, = 550 nair=1.0 Boundary ON= 450 num Solution Given : 0, = 550 OF = 450 Sample P nair=1.0 A light ray Asked: the air. Two dif angles. The re Speed of light ray (c) at an unknown medium=? 26.50 with refe Process: these glasses A Determine the n of the unknown material. they pass thro Using Snell's Law of Refraction n, sin , = n2 sin @2 where nair Sin 0; = num Sin 0, sine; (sin55 Solution therefore num = nair sin er = 1.00 sin45 Given: = 1.16 0 = 550 0, = 28.50 Determining the speed using the formula n = - 0, = 26.50 C 3x10m/s V = = = - n 1. 16 = 2.59x10# m/s Asked: nrg nyg Vr, a Process: a. Determining A Using Snel nair Sin 0; for red: for violetOf Task No. 2: Problem Solving (refraction) dex of Directions: Solve the problem below in your answer sheet. Identify the given data mal. and the unknown. A light ray coming from air penetrates an unknown material at an angle of incidence equal to 65" with respect to the normal. The air has a refractive index of 1.0 and the unknown material causes the light ray to bend at 20' with the normal. How fast will the light moves on this material? Dair=1.0 Boundary Sample Problem on Dispersion A light ray hits a glass at an incident angle of 550 with reference to the normal in the air. Two different glass were observed that causes the bending of light at different angles. The red color light makes an angle of 28.50 while the violet makes an angle 26.50 with reference to the normal of the glass. What are the index of refraction of these glasses for different colors of light? What are the speeds of the two colors as they pass through this medium? 155 Solution 45 Given: 0 = 550 0, = 28. 50 for red 0, = 26. 5" for violet Asked: nig nyg, Vr, and Vv Process: a. Determining the refractive index of the Glass used Using Snell's Law of Refraction n, sin d, = n2 sin 02 naly Sin Of = notas's sin 0, sine, for red: nglass = nair sino, " = 1.00 (sin55 sin28. 5)= = 1.72 for violet: nglass = Hair sin 0, sinet = 1.00 (- sin55 sin26. 5 = 1.84DoTED b. The Speeds of the two colors for red: v= = 3x103m/s IV. Answer Key 1.72 = 1.74x108m/s for violet: D = 3x10#m/S 1.84 = 1.63x108 m/s Task No. 3: Problem Solving(dispersion) 2x10*m/s Directions: Solve the problem below in your answer sheet. Identify the given data = 1.295 and the unknown. A light ray hits a glass at an incident angle of 70 with reference to the normal in the air. Two different glass were observed that causes the bending of light at different angles. The red color light makes an angle of 48.50 while the violet makes an angle 46.50 with reference to the normal of the glass. What are the indices of refraction of these glasses for different colors of light? What are the speeds of the two colors as they pass through this medium? Sample Problem on Polarization If the beam of polarized light has 1/5th of its initial intensity after passing an analyzer what is the angle between the axis of the analyzer and the beam's initial V . Other Refere amplitude? 'Resnick, Halliday, Given: Wiley.com,2021.ht 1= 1/5th 10=0.2 lo 9&item Typeld=BK Asked : 8 book-info.com - Using Malus Law I = 0.21, = locos20 Solved Problems cos20 = 0.2 cos 0 = VO.2 = 0.447 thus 0 = cos 10.447= 63.450 https://www.book Task No. 4: Problem Solving (polarization) Directions: Solve the problem below in your answer sheet. Identify the given data "University Physi and the unknown. Download." 1lib. https://1lib.ph/bo If the beam of polarized light has 1/6th of its initial intensity after passing an analyzer what is the angle between the axis of the analyzer and the beam's initial amplitude? "Physics for Scie and Streaming IV. Reflection https://archive. learned that ... I realized that... I need more information about..1 5th Edition - Student Companion Site." Other References and Electronic Sources V. Task No. 1: Problem Solving (reflection) Ans. 9, = 51. 340 Task No. 2: Problem Solving (refraction) Ans. v=1.13x108 m/s Task No. 3: Problem Solving (dispersion) a. for red: nglass = 1.255 for violet: nglass = 1.295 b. for red: v = 2. 4x108m/s for violet: v = 2. 32x108m/s Task No. 4: Problem Solving (polarization) 0 = 65. 800 IV. Answer Key