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Please answer all parts of the question. #4. Open Addressing Strategies (8 points) (a) (2 pts): Show the table that results when 9, 32,1,66, 40,
Please answer all parts of the question.
#4. Open Addressing Strategies (8 points) (a) (2 pts): Show the table that results when 9, 32,1,66, 40, 20,51,10 are cumulatively inserted in that order into an initially empty hash table of size 11 with linear probing and h'(k) - k mod 11 h(k,i) - (h'(k) + i) mod 11, where the first probe is probe i-0 Draw this and the next result as horizontal arrays indexed from 0 to 10 as shown below. (You can fill in the Google Doc table.) Show your work in part (b) to justify your answer! 2 4 10 (b) (1 pt): How many re-hashes after collision are required for this set of keys? Show your work here so we can give partial credit or feedback if warranted (c) (2 pts): Show the table that results when 9, 32, 1, 66, 40, 20, 51, 10 are cumulatively inserted in that order into an initially empty hash table of size m= 11 with double hashing and h(k,f)- (h,(k) + ih2(k)) mod 11 h,(k) - k mod 11 h2(k)- 1 +(k mod 7) Refer to the code in the book for how i is incremented. Show your work in part (d) to justify your answer! 10 (d) (1 pt): How many re-hashes after collision are required for this set of keys? Show your work here so we can give partial credit or feedback if warranted (e) (2 pts): Open addressing insertion is like an unsuccessful search, as you need to find arn empty cell, i.e., to not find the key you are looking for! If the open addressing hash functions above were uniform hashing, what is the expected number of probes at the time that the last key (10) was inserted? Use the theorem for unsuccessful search in open addressing and show your work. Answer with a specific number, not O or ThetaStep by Step Solution
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