Question
Please answer in Python (no imports, no list comprehensions) Given a file with an encoded message and the parameter skip (as a positive integer), parse
Please answer in Python (no imports, no list comprehensions)
Given a file with an encoded message and the parameter skip (as a positive integer), parse through it line by line and return a decoded version of the file in one string, with each decoded message in a new line. Dont remove the extra empty line (last line) from the output string. Then, skip through lines based on the 'slip' parameter that will tell you how many lines to skip through as you parse through the file. Return the string with only the required information after 'skip'.
while decoding, ignore: all exclamation points (!), question marks (?), semicolons (;), dollar signs ($) and any whitespaces.
(example): if input has 6 lines and skip = 1, output will keep line 1, skip line 2, keep line 3, skip line 4, etc. If skip = 2 then output will keep line 1, skip lines 2 and 3, keep line 4, etc.
examples:
Input file contents, skip = 2 | process | Output file contents: |
j!!!!a?$;ck! $r?ea!che;;r 2!!3@4 b#l31oo%m@^ w!$ay$? FSD!@si$$%m3~on f!is#he%r! 1?2!!1 r$oc!ke!??fe?l!!l$e;r av;;e?n$$u$e!! 3;2'1 ?fu$l!!leH##r ;"?dr^i~!v@e$ @@4!:)5#0???p1m# 7?$/2!!9? 0!!6.;??4$5! | line1 --> keep line2 --> skip line3 --> skip line4 --> keep line5 --> skip line6 --> slip line7 --> keep | jack reacher 121 rockefeller avenue 7/29 06.45 |
"""
>>> print(decode_and_skip('files/encoded_1.txt', 2).strip()) stevie wonder Lafayette Street 8/09 1-2 >>> print(decode_and_skip('files/encoded_2.txt',0).strip())
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