PLEASE ANSWER IT CORRECTLY bASED ON GIVEN PROVIDED

EXERCISE: A fluid is cooled from 150F to 80F in the inner pipe of a double-pipe heat exchanger. The cooling fluid flows counter-currently, entering the jacket at 65F and leaving at 75F. The other given data are as follows (Basis: 1 ft length of concentric tubes): inner diameter of inner tube = 0.0621 ft outer diameter of inner tube = 0.072 ft fouling factor on inner surface of inner tube = 550 Btu/ft?. hr: F radiative heat transfer coefficient on inner fluid side = 450 Btu/ft.hr F convective heat transfer coefficient through inner fluid = 130 Btu/ft2. hr. OF thermal conductivity of inner tube = 26 Btu/ft.hr OF convective heat transfer coefficient on outer fluid side = 300 Btu/ft2.hr - OF radiative heat transfer coefficient on outer fluid side = 500 Btu/ft2.hr . F fouling factor on outer surface of the inner tube = 1000 Btu/ft?. hrOF NOTE: Use subscript i for inner surface or inner fluid and o for outer surface or fluid. Example: hd, fouling on outer tube surface 1. Solve for the overall heat-transfer coefficient from the sum of individual resistances between the bulk temperature of inner and outer fluids. 2. Calculate the constant rate of heat transfer, q, in Btu/ft.hr 3. Using the formula hi = (hc + hr + hd), find T, the inner surface temperature of the inner tube. 4. Determine the outer surface temperature Ty of the inner tube