Please answer question correctly and show the result of the working code. The actual and demo code is provided .

This assignment is about using the Java Collections Framework to accomplish some basic text-processing tasks.

These questions involve choosing the right abstraction (Collection, Set, List, Queue, Deque, SortedSet, Map, or SortedMap) to efficiently accomplish the task at hand. The best way to do these is to read the question and then think about what type of Collection is best to use to solve it. There are only a few lines of code you need to write to solve each of them.

Unless specified otherwise, sorted order refers to the natural sorted order on Strings, as defined by String.compareTo(s).

Que:Read the input one line at a time and, instead of outputting the line, output the number of times you have already seen that line. Again, take special care so that a file with a lot of duplicate lines does not use more memory than what is required for the number of unique lines.

Actual Code

package comp2402a1;

import java.io.BufferedReader; import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter;

public class Part7 { /** * Your code goes here - see Part0 for an example * @param r the reader to read from * @param w the writer to write to * @throws IOException */ public static void doIt(BufferedReader r, PrintWriter w) throws IOException { // Your code goes here - see Part0 for an example }

/** * The driver. Open a BufferedReader and a PrintWriter, either from System.in * and System.out or from filenames specified on the command line, then call doIt. * @param args */ public static void main(String[] args) { try { BufferedReader r; PrintWriter w; if (args.length == 0) { r = new BufferedReader(new InputStreamReader(System.in)); w = new PrintWriter(System.out); } else if (args.length == 1) { r = new BufferedReader(new FileReader(args[0])); w = new PrintWriter(System.out); } else { r = new BufferedReader(new FileReader(args[0])); w = new PrintWriter(new FileWriter(args[1])); } long start = System.nanoTime(); doIt(r, w); w.flush(); long stop = System.nanoTime(); System.out.println("Execution time: " + 10e-9 * (stop-start)); } catch (IOException e) { System.err.println(e); System.exit(-1); } } }

Demo Code

package comp2402a1;

import java.io.BufferedReader; import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.HashSet; import java.util.Iterator; import java.util.Set;

public class Part0 { /** * Read lines one at a time from r. After reading all lines, output * all lines to w, outputting duplicate lines only once. Note: the order * of the output is unspecified and may have nothing to do with the order * that lines appear in r. * @param r the reader to read from * @param w the writer to write to * @throws IOException */ public static void doIt(BufferedReader r, PrintWriter w) throws IOException { Set s = new HashSet<>();

for (String line = r.readLine(); line != null; line = r.readLine()) { s.add(line); }

for (String text : s) { w.println(text); } }

/** * The driver. Open a BufferedReader and a PrintWriter, either from System.in * and System.out or from filenames specified on the command line, then call doIt. * @param args */ public static void main(String[] args) { try { BufferedReader r; PrintWriter w; if (args.length == 0) { r = new BufferedReader(new InputStreamReader(System.in)); w = new PrintWriter(System.out); } else if (args.length == 1) { r = new BufferedReader(new FileReader(args[0])); w = new PrintWriter(System.out); } else { r = new BufferedReader(new FileReader(args[0])); w = new PrintWriter(new FileWriter(args[1])); } long start = System.nanoTime(); doIt(r, w); w.flush(); long stop = System.nanoTime(); System.out.println("Execution time: " + 10e-9 * (stop-start)); } catch (IOException e) { System.err.println(e); System.exit(-1); } } }