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PLEASE ANSWER THE FIRST 2 QUESTIONS IN THE FIRST PIC. THANKS! Write your answer an a separate sheet at paperl'natebaak. 1. Use the results in
PLEASE ANSWER THE FIRST 2 QUESTIONS IN THE FIRST PIC. THANKS!
Write your answer an a separate sheet at paperl'natebaak. 1. Use the results in Example 2 to calculate the escape speed fair a spacecraft a. from the surface at Mars {m = 6.42 x 1i]23 kg; r = 3.49 x m\" m) b. tram the surface of Jupiter [m = 1.90 x 1D\" kg: r = 6.91 :4 107m}. 2. A projectile is fired straight upward from the Earth's surface at the South Pole with an initial speed equal to one third the ESCUpe speed. Ignoring air resistance. determine haw far from the center at the Earth the projectile travels before stopping momentarily. Example 2 (Young, Freedman, and Lewis 2012). In Jules Verne's 1865 story, sunk in the Earth in Florida. (a) Find the minimum muzzle speed needed to shoot a shell straight up to a height above the Earth equal to the Earth's radius RE. (b) Find the minimum muzzle speed that would allow a shell to escape from the Earth completely (the escape speed). Neglect air resistance, the Earth's rotation, and the gravitational pull of the moon. The Earth's radius and mass are RE =: 6.38 x 10 m and mg = 5.98 x 102* kg.Solution: The only force acting once the shell leaves the cannon muzzle will be gravity. Hence, we will use the conservation of mechanical energy to find the speed in both (a) and (b). (a) In this part, we will have ri = RE and r, = 2Rs , and v, = 0. Thus, 1 5 mv?+(- -GM.my -GM,my RE mo, 2 + 2RE -GM. IIIY = mv,2 +- =0 + -GM.my RE 2RE 1 -GM,mLY -GM.THY myz= 2 2RE RE GM.m 2RE GMe RE GM. Vv2 = RE (6.67 x 10 1IN . m'/kg2) (5.98 x 1024 kg) V = 6.38 x 106 m = 7900 m/s (b) In this part, we will have n = Rg and since ry = oo , just like in Example 1. _ = 0. Still, v/ = 0. -GM. my 5mv 2 + mv, 2 + -GM.my RE 2RE GM,my =0 +0 RE GM. m = mv 2 = RE 2GM. RE 2GM. RE 2(6.67 x 10-11N . m2/kg2) (5.98 x 1024kg) V. = 6.38 x 105m = 1.12 x 10* m/sStep by Step Solution
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