Please answer the last question that says : How does the result compare to the actual circumference of 4.4 cm ?

Math 150 Intro to Statistics BMCC Spring 2022 Homework: Section 10.2 Homework Question 8, 10.2.27 HW Score: 66.67%, 6 of 9 points Part 3 of 3 O Points: 0 of 1 Save Find the regression equation, letting the diameter be the predictor (x) variable, Find the best predicted circumference of a marble with a diameter of 1.4 cm. How does the result compare to the actual circumference of 4.4 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.3 23.6 4.3 21.7 6.9 40 21.2 Circumference 22.9 74.1 13.5 68.2 21.7 12.6 66 6 Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r Critical Values of the Pearson Correlation Coefficient r a = 0.05 a = 0.01 NOTE: To test Ho: p = 0.950 10.990 against H1: p #0, rejec 0.878 0.959 f the absolute value of The regression equation is y = 0.0101 + 3.14078 x 0.811 0.917 greater than the critical 10.754 0.875 value in the table. (Round to five decimal places as needed.) 8 0.707 0.834 9 0.666 0.798 The best predicted circumference for a diameter of 1.4 cm is 4.4 cm. 10 0 632 0.765 (Round to one decimal place as needed.) 11 10.602 0.735 How does the result compare to the actual circumference of 4,4 cm? 12 0.576 0.708 13 0.553 0 684 O A. Since 1.4 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. 14 0.532 0.661 15 0.514 0.641 O B. Even though 1.4 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. 10.497 0.623 O C. Since 1.4 cm is within the scope of the sample diameters, the predicted value yields the actual circumference 10.482 0.60 18 0.468 0.590 O D. Even though 1.4 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0 361 0.463 35 0.335 0.430 Help me solve this View an example Get more help - 40 0.312 0.402 45 10.294 0.378