PLEASE ANSWER THESE ASTRONOMY QUESTION NUMBER 2 WITH ALL PARTS. THE SIG DIGITS SHOULD BE 4. PLEASE TRY TO TYPE EVERYTHING SP I CAN EASILY READ

The figure below shows the positions of objects in the sky as seen from Waterloo in "natural" coordinates of Azimuth (0 degrees is to the North, 90 degrees is East, 180 degrees is South) and Elevation (0 degrees is the horizon and 90 degrees is directly overhead). This is just half of the sky but the other half (from Azimuth of 180 to 360 is a perfect mirror reflection of this). Note that the Elevation of 0 is the position where an object rises above the horizon (the Elevation of 0 on the reflected figure shows the position at setting).

Azimuth and Elevation from UWaterloo 40 deg 50 deg -1 hr 80 - - 60 deg 30 deg - -2 hr 20 deg 70 deg 60 -3 hr 10 deg -4 hr 0 deg Elevation 40 -10 deg -5hr -6 hr -20 deg 20 -7 hr -8 hr -9 hr 150 0 100 50 0 Azimuth