Please assist and make correction where necessary.

I am having trouble with the 3 Question.

a) How to identify the p value on the normal table Z or student's t table (df =8)

b) Do I reject the null hypothesis?

c) Give a statement of the results.

Join Count Analysis County Number of Links L - 1 L ( L - 1 ) Litchfield 3-1 = 2 3 . 2 = 6 2 Hartford 5 -1 = 4 5.4 = 20 3 Tolland 3 - 1 = 2 3.2 = 6 F N N Q U W 4 windham 2-1 = 1 2 . 1 = 2 5 Fair Field 2-11 = 1 2 - 1 = 2 6 New Haven 4 - 1 = 3 4 . 3 = 12 7 Middlesex 3 3-1 = 2 3. 2 = 6 8 New London 4 4 - 1 = 3 4. 3 x = 12 Total 26 18 164 Links Number of Black downs areas : B= 12 Number of white areas : W = 16 1 . Count total number of Joins - 13 D> 2. Count the observed number of Black &white Joins. 3 Calculate the expected number of BAN Black. White Joins . Formula 15.2 EBW = 2 JBW 2 . d . B. W n ( n -1 ) no (n - 1) 2 x 13 x 2 x 6 = 312 = 312 => 5.57 8 x (8-1) 8x7 565 Calculate standard error of expected B-W Joins using Formula 15.3 6 BW EBW + . EL ( L - 1 ) BW + 4 [ J ( J - 1 ) - E L ( L . I) J B ( B- 1) W ( W-1) - EBW N. ( N-1 ) NON-I) (N- 2) (N-3) DBW 5:57+ 66. (2).16) + 4 [26 ( 25) - 667 - 2(1) (6)(5)- 5.57 8 (8 - 1 ) 8 (7) (6) ( 5 ) 5 BW 5.57+ 792 + 40650 - 66]. 60 56 -31 . 02 1680 OBW /5.57 + 14.14 + 4 [ 584.] . 60 - 31.02 1680 OBW 5.57 + 14.14 + 83.71 - 31. 02 QBW 103. 42 - 31.02 QBW 72 . 4 QBW = 18.51 6. Calculate the Z Value using Formula 15.1 Zb = DBW - EBW DBW 13 - 5.57 = 7.43 => 0.8731 8.51 . 8.51