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Please be careful with the memory leak, the professor will check the coding with Valgrind in matrix. The code needs to run on matrix. Thank

Please be careful with the memory leak, the professor will check the coding with Valgrind in matrix. The code needs to run on matrix. Thank you in advanced.

The Numbers Module

Your task for this lab is to complete the implementation of the Numbers class. This class reads several double values from a file (one number per line) and holds them dynamically in memory. Then the caller application has the option of adding numbers to the collection. This Module can provide information about the numbers and display them on the screen:

  • The Module can display the values in ascending order (sort).
  • The Module can find the largest value
  • The Module can find the smallest value
  • The Module can calculate the average of the values in the collection

Also The Numbers class has the following capabilities:

  • A Numbers object can safely be copied or assigned to another Numbers module
  • A Numbers object can be displayed or streamed into an istream object.
  • A Numbers object can be read from an istream object.

When the Numbers object goes out of the scope the values overwrite the old values in the file, ONLY IF the object is the original object and not a copy..

numberCount() (to be implemented)

This function (that is incapable of modifying the currect object), will return the number of lines in the data file (hence returning the number of double values in the file).

  • Implement an instance of ifstream to open the data file name.
  • While the ifstream object has not failed keep reading single characters from the file
  • Count the number of newline characters in an integer variable
  • Return the number of counted newlines when all characters in the file are scanned.

load() (to be implemented)

This function returns true if all the double values are read from the data file and stored in a dynamically alocated memory pointed by m_numbers, othewise returns false.

  • If number of double values in the file is greater than zero (m_numCount > 0)
  • Allocate memory to hold the double values in an array pointed by m_numbers.
  • Implement an instance of ifstream for the data file
  • While the ifstream object has not failed, keep reading double values from the file into the elements of m_numbers dynamic array (as you do with cin)

make sure to add to the index of the loop only if the istream object has not failed in its last reading

  • return true if the number of read doubles, is equal to the m_numCount member variable.

save() (to be implemented)

  • If the current object is the original and it is not in safe empty state
  • Implement an instance of ofstream to overwrite the dat afile
  • Write all the elements of the m_numbers array using the ofstream object.
  • Write a newline after each double value.

Operatro += (to be implemented)

Overload the += operator to add a single double value to the list of numbers in the array and then return the reference of the current object.

You need to increase the size of the allocated memory by one (add one double to the array), to be able to do this.

Here is the sequence of the actions to be taken to resize memory:

  • Implement a temporary local double pointer and allocate memory with the increased size
  • Copy all the current values to the newly allocated memory.
  • Update the size of the data to the new size
  • Now that all the values are copied to the new memory, delete the original allocated memory
  • Set the original data pointer to point to newly allocated memory

Using the above guidelines; in our case, do the following only if the object is not in an empty state:

  • Implement a temp double pointer and allocate memory to the size: m_numCount + 1
  • In a loop, copy all the double m_numbers elements to the double temp number elements (up to m_numCount)
  • Add one to m_numCount (to update the number of double values)
  • copy the value of the double argument to the last element of the double temp array (and therefore add the double value to the list)
  • delete m_numbers to get rid of the ariginal allocated memory
  • Set m_numbers to temp pointer; by doing this m_numbers will point to the newly allocated memory.
  • sort the numbers so the added number stands at the proper location in the array

Regardless of the object being empty or not return the reference of the current object.

display function. (to be implemented)

ostream& display(ostream& ostr) const

  • if the object is empty, write: "Empty list".
  • if the object is not empty start by writing: "=========================" on ostr and then go to newline
  • if the object is flagged as original, then write the file name otherwise write "*** COPY ***" and then go to new line
  • write all the double numbers seperated by ", " (A comma and a space) and then go to new line
  • write "-------------------------" and go to new line
  • Write "Total of " << m_numCount << " number(s)" and go to new line
  • write "Largest number: " and the largest number in the list and go to new line
  • write "Smallest number: " and the smallest number in the list and go to new line
  • write "Average : " and the average of all the numbers inthe list and go to new line
  • write "=========================" and DO NOT GO TO NEWLINE

At the end return the ostr object.

Execution sample

A Numbers object that has the double values 34.1, 3, 6, 12.2 and 34.56 in a file called numbers.txt should be displayed as follows:

========================= numbers.txt 3, 6, 12.2, 34.1, 34.56 ------------------------- Total of 5 number(s) Largest number: 34.56 Smallest number: 3 Average : 17.972 ========================= 

If a Number object is empty, it will be displayed as follows:

Empty list 

Helper function overlaods (to be implemented)

ostream& operator<<(ostream& os, const Numbers& N);

Overload the insertion operator to display the Numbers object using istream.

  • call the display fucntion of N and return it

istream& operator>>(istream& istr, Numbers& N);

Overload the extraction operator to display the Numbers object using istream.

  • read a double value using istr
  • add the double value to N using += operator
  • return istr;

Numbers.h

#ifndef SDDS_NUMBERS_H_ #define SDDS_NUMBERS_H_ #include  namespace sdds { class Numbers { double* m_numbers; char* m_filename; bool m_isOriginal; int m_numCount; bool isEmpty()const; void setEmpty(); void setFilename(const char* filename); void sort(); public: Numbers(); Numbers(const char* filename); double average()const; double max()const; double min()const; ~Numbers(); }; } #endif // !SDDS_NUMBERS_H_ 

Numbers.cpp

#define _CRT_SECURE_NO_WARNINGS #include  #include  #include "Numbers.h" #include "Numbers.h" // intentional using namespace std; namespace sdds { Numbers::Numbers() { setEmpty(); m_isOriginal = false; } Numbers::Numbers(const char* filename) { setEmpty(); m_isOriginal = true; setFilename(filename); m_numCount = numberCount(); if (m_numCount == 0 || !load()) { delete[] m_numbers; delete[] m_filename; setEmpty(); m_isOriginal = false; } else { sort(); } } Numbers::~Numbers() { save(); delete[] m_numbers; delete[] m_filename; } bool Numbers::isEmpty() const { return m_numbers == nullptr; } void Numbers::setEmpty() { m_numbers = nullptr; m_filename = nullptr; m_numCount = 0; } void Numbers::setFilename(const char* filename) { delete[] m_filename; m_filename = new char[strlen(filename) + 1]; strcpy(m_filename, filename); } void Numbers::sort() { int i, j; double temp; for (i = m_numCount - 1; i > 0; i--) { for (j = 0; j < i; j++) { if (m_numbers[j] > m_numbers[j + 1]) { temp = m_numbers[j]; m_numbers[j] = m_numbers[j + 1]; m_numbers[j + 1] = temp; } } } } double Numbers::average() const { double aver = 0.0; if (!isEmpty()) { for (int i = 0; i < m_numCount; i++) aver += m_numbers[i]; aver = aver / m_numCount; } return aver; } double Numbers::min() const { double minVal = 0.0; if (!isEmpty()) { minVal = m_numbers[0]; for (int i = 1; i < m_numCount; i++) if (minVal > m_numbers[i]) minVal = m_numbers[i]; } return minVal; } double Numbers::max() const { double maxVal = 0.0; if (!isEmpty()) { maxVal = m_numbers[0]; for (int i = 1; i < m_numCount; i++) if (maxVal < m_numbers[i]) maxVal = m_numbers[i]; } return maxVal; } } 

Tester Programm // main

 #include  #include  #include "Numbers.h" using namespace sdds; using namespace std; void startTest(int n) { cout << "Test"; for (int i = 0; i < 30; i++) cout << " " << n; cout << endl; } void endTest(int n) { cout << "End Test"; for (int i = 0; i < 28; i++) cout << " " << n; cout << endl; } void resetFile(const char* fname) { ofstream f(fname); f << 6 << endl << 12.2 << endl << 3 << endl << 34.1 << endl; } void displayFile(const char* fname) { ifstream f(fname); char ch; cout << endl << "Content of \"" << fname << "\"" << endl << "*****************************************************************" << endl; while (f.get(ch)) { cout << ch; } cout << "*****************************************************************" << endl; } void displayList(Numbers N) { cout << "Add a number to the list: "; cin >> N; cout << N << endl; } void test1() { startTest(1); Numbers N("numbers.txt"); N += 34.56; cout << N << endl; displayList(N); endTest(1); } void test2() { startTest(2); Numbers N("numbers.txt"); Numbers M(N); Numbers L; Numbers BAD("BadFileName.txt"); cout << N << endl << M << endl << L << endl << BAD <> N; addnum >> N; addnum >> N; output << N << endl; endTest(3); } int main() { resetFile("numbers.txt"); test1(); displayFile("numbers.txt"); test2(); displayFile("numbers.txt"); test3(); displayFile("numbers.txt"); displayFile("add.txt"); displayFile("output.txt"); return 0; }

EXPECTED OUTPUT

Test 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ========================= numbers.txt 3, 6, 12.2, 34.1, 34.56 ------------------------- Total of 5 number(s) Largest number: 34.56 Smallest number: 3 Average : 17.972 ========================= Add a number to the list: 1000 ========================= *** COPY *** 3, 6, 12.2, 34.1, 34.56, 1000 ------------------------- Total of 6 number(s) Largest number: 1000 Smallest number: 3 Average : 181.643 ========================= End Test 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 Content of "numbers.txt" ***************************************************************** 3 6 12.2 34.1 34.56 ***************************************************************** Test 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ========================= numbers.txt 3, 6, 12.2, 34.1, 34.56 ------------------------- Total of 5 number(s) Largest number: 34.56 Smallest number: 3 Average : 17.972 ========================= ========================= *** COPY *** 3, 6, 12.2, 34.1, 34.56 ------------------------- Total of 5 number(s) Largest number: 34.56 Smallest number: 3 Average : 17.972 ========================= Empty list Empty list ========================= numbers.txt 3, 6, 12.2, 34.1, 34.56, 1000 ------------------------- Total of 6 number(s) Largest number: 1000 Smallest number: 3 Average : 181.643 ========================= ========================= *** COPY *** 3, 6, 12.2, 34.1, 34.56, 1000 ------------------------- Total of 6 number(s) Largest number: 1000 Smallest number: 3 Average : 181.643 ========================= ========================= *** COPY *** 3, 6, 12.2, 34.1, 34.56, 1000 ------------------------- Total of 6 number(s) Largest number: 1000 Smallest number: 3 Average : 181.643 ========================= End Test 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 Content of "numbers.txt" ***************************************************************** 3 6 12.2 34.1 34.56 1000 ***************************************************************** Test 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 In this test we use your insertion and extraction operators to do File IO. This makes sure your implementation is done correctly using the reference of istream and ostream and NOT cin and cout End Test 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 Content of "numbers.txt" ***************************************************************** -5 3 6 12.2 34.1 34.56 222.1 333.2 1000 ***************************************************************** Content of "add.txt" ***************************************************************** -5 222.1 333.2 ***************************************************************** Content of "output.txt" ***************************************************************** ========================= numbers.txt -5, 3, 6, 12.2, 34.1, 34.56, 222.1, 333.2, 1000 ------------------------- Total of 9 number(s) Largest number: 1000 Smallest number: -5 Average : 182.24 ========================= *****************************************************************

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