Please calculate: a$)$the potential of the Cu$|$Cu$2+$ half$-$cell $(0\mathrm{.}25$ M$)$ based on the measured EMF$[$V$]$ value $-0\mathrm{.}017$ b$)$the half$-$cell potential of Cu$|$Cu$2+(0\mathrm{.}25$ M$)$ at a temperature of $25$ oC using the Nernst equation:

E $=$ Eo $($RT$/$nF$)$ln Q $=$ Eo $(0\mathrm{.}0591$V$/$n$)$log Q$,$ where Q is the mass action expression for the reduction half$-$reaction