please calculate option b and question 4

b) A membrane having a porosity of 0.3 , average pore size of 0.04m, average pore tortuosity of 1.1 , surface area of 2cm2 and thickness of 0.1mm separates two water-filled, well-mixed chambers one having a volume of 10ml and the other having a volume of 20ml. The content of the 10ml chamber was replaced with 10ml of 1mg/ml insulin solution at t=0. Determine if insulin is hindered by the pores of the membrane and calculate the insulin concentration in the other chamber after 5 hours. Assume that there is no convective flow of solvent through the membrane. This experiment was carried out at 20 degrees centigrade. MW of insulin =5800Da(15pts) 4-) (25 pts) Murine monoclonal antibody is to be recovered from 100 liters of cell culture supernatant having antibody concentration of 0.2kg/m3 by ammonium sulphate precipitation. MW of antibody =155kDa and MW of (NH4)2SO4=132kg/kgmole. How many kilograms of ammonium sulphate would be needed to precipitate 95% of the antibody? A preliminary experiment carried out using 1 liter of a similar cell culture supernatant showed that 180mg of the antibody could be precipitated at 1.75M ammonium sulphate concentration. The solubility of the antibody in salt free water is 390kg/m3. b) A membrane having a porosity of 0.3 , average pore size of 0.04m, average pore tortuosity of 1.1 , surface area of 2cm2 and thickness of 0.1mm separates two water-filled, well-mixed chambers one having a volume of 10ml and the other having a volume of 20ml. The content of the 10ml chamber was replaced with 10ml of 1mg/ml insulin solution at t=0. Determine if insulin is hindered by the pores of the membrane and calculate the insulin concentration in the other chamber after 5 hours. Assume that there is no convective flow of solvent through the membrane. This experiment was carried out at 20 degrees centigrade. MW of insulin =5800Da(15pts) 4-) (25 pts) Murine monoclonal antibody is to be recovered from 100 liters of cell culture supernatant having antibody concentration of 0.2kg/m3 by ammonium sulphate precipitation. MW of antibody =155kDa and MW of (NH4)2SO4=132kg/kgmole. How many kilograms of ammonium sulphate would be needed to precipitate 95% of the antibody? A preliminary experiment carried out using 1 liter of a similar cell culture supernatant showed that 180mg of the antibody could be precipitated at 1.75M ammonium sulphate concentration. The solubility of the antibody in salt free water is 390kg/m3