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Please explain each step :) I got confused when I plug in and then solve. To a calorimeter containing 50.0g water at 23.4C is added
Please explain each step :) I got confused when I plug in and then solve.
To a calorimeter containing 50.0g water at 23.4C is added 25.0g of aluminum metal (which has been heated to 100C ). What is the final temperature reached by the water after mixing? Show all work to receive credit. Assume no heat is lost to the calorimeter or the surroundings, cp(water)=4.18J/(gC);cp(uaminum)=0.89J/(gC) (3 points)Step by Step Solution
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