Please explain how you get the answer

3. A computer has 64-KB virtual address space and 32-KB physical address space. The page size is 4 KB. At an instant f, the mapping between virtual address space and physical address space is shown in Fig.2. Answer the following questions Virtual 1) Compute virtual page number and offset for the virtual addresses adres space 60K-64KX 56K-60K 52K-56K | X 48K-52K X 44K-48K 7 40K-44K X 36K-40K 5 4090, 8300, 16500, and 48400. Virtual page 32K-36KX 28K-32K X Physical memory address 28K-32K 24K-28K 20K-24K 20K-24K3 16K-20K4 12K-16K 0 8K-12K 6 16K-20K 12K-16K 8K-12K 4K-8K OK-4K 2 OK-4K Page frame Fig.2 2) Compute the physical address for the virtual addresses 4090, 8300, 16500, and 48400