Please explain with steps. Thank You.

Let f : R* - R' be given by f(x, y, z) = (e # + 2, sin(a + y + z)), and let g : R- - R be a differentiable function such that Vy(1, 0) = i -2j. Compute the gradient of g(f(r, y, =)) at the point (r, y, =) = (0, 0, 0).the growment of the function 9: 182> IR is Vg(10)= i-2] i. e. Vg ( 1, 0) = 29 (1,0 ) 1+ 28 ( 10 ) OX = 1 - 23 2 8 ( 1,0 ) = 1 and 28 ( 170 ) =-2 ay We have to find the gradient of g ( fix,y ,z ) ) at ( x , y ,z ) = ( 0 , 0 , 0)Now , 9 ( fea, y , 2) ) at ( 2 , y , 2 ) = ( 0 , 9 , 0 ) 9 ( f (0, 0, 0) ) 9 ( 1, 0 ) f ( o , 0 , 0 ) = (1 ,0 ) so , the gradient of 9 (f(x, 1,2 ) ) of (* ,y , 2 ) = ( 0 , 0 , 0 ) means gradient of 9 ( 1,0 ) Vg ( 10 ) = 29(10) 7+09(1,0 ) ] 7 - 2 j