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If Question Help A survey showed that 76% of adults need correction (eyeglasses, contacts, surgery, etc. ) for their eyesight. If 19 adults we randomly selected, find the probability that no more than 1 of them need correction for their eyesight Is 1 a significantly low number of adults requiring eyesight correction? The probability that no more than 1 of the 19 adults require eyesight comection s(]. (Round to three decimal places as needed.) Is 1 a significantly low number of adults requiring eyesight correction? Note that a small probability is one that is less than 0.05. O A No, because the probability of this occurring is small. B. Yes, because the probability of this occurring is small O C. Yes, because the probability of this occurring is not small. O D. No, because the probability of this occurring is not small,Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the [bellhood that each baby will be a girl, but assume that the method has no affect, so the probability of a girl is 0.5. Assume that the groups consist of 31 couples, Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 31 births The value of the mean is p=]. (Type an integer or a decimal. Do not round.) The value of the standard deviation is a =_ (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low of significantly high. Values of girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Found to one decimal place as needed.) c. Is the result of 29 girls a result that is significantly high? What does it suggest about the offectiveness of the method? The result is significantly high, because 29 girls is| greater than girls. A result of 29 girls would suggest that the method (Round to one decimal place as needed.)