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Please help! 1. v64m2 25 Evaluate the integral: f 33 do: (A) Which trig substitution is correct for this integral? 1 O (I: = aseC(6)

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v64m2 25 Evaluate the integral: f 33 do: (A) Which trig substitution is correct for this integral? 1 O (I: = aseC(6) 25 0 = _ a: 64 sec(6) 8 O a: = Esecw) 5 O a: = sec(6) 8 5 . O a: = gsmw) (B) Which integral do you obtain after substituting for :13? Note: to enter 6, type the word theta. _d9 (C) What is the value of the above integral in terms of 6? :H (D) What is the value of the original integral in terms of (1:? Note: WAMAP does not recognize the inverse secant (arcsec) function. You will need to use another inverse trig function when you fill in your answer below. :u: Evaluate the integral: 53 V 1 + 1003:2033: (A) Which trig substitution is correct for this integral? 0 a: = 10 008(6) 0 a: = 100 sin(9) 1 O a: = 10tan(6) O a: = i1:53.1109) 100 O a: = isec(t'}) 10 O a: = isew?) 100 (B) Which integral do you obtain after substituting for :1: and simplifying? Note: to enter 6, type the word theta. _d6 (C) What is the value of the above integral in terms of 6? C (D) What is the value of the original integral in terms of 3:?

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