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Please help, and please show work A sample of 20 items provides a sample standard deviation of 9.5. Test the following hypotheses using a =

Please help, and please show work

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A sample of 20 items provides a sample standard deviation of 9.5. Test the following hypotheses using a = 0.05. What is your conclusion? . 2 \"0'6 50 . 2 Ha. 0' > 50 Use the p-value approach. Find the value of the test statistic. |:| Find the p-value. (Round your answer to three decimal places.) State your conclusion. 0 Reject H0. We conclude that the population variance is greater than 50. 0 Do not reject \"0' We conclude that the population variance is greater than 50. O Reject H0. We conclude that the population variance is not greater than 50. 0 Do not reject HO' We conclude that the population variance is not greater than 50. Use the critical value approach. Find the value of the test statistic. |:| State the critical values for the rejection rule. {Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.) State your conclusion. 0 Reject H0. We conclude that the population variance is greater than 50. 0 Do not reject H0. We conclude that the population variance is greater than 50. (a) What is your conclusion if nl = 2]., 512 = 2.2, n2 = 26, and 522 = 1.0? Use a = 0.05 and the p-value approach. Find the value of the test statistic. |:| Find the p-value. (Round your answer to four decimal places.) State your conclusion . O Reject HO' We cannot conclude that 012 i 022. 2 2 0 Do not reject H0. We cannot conclude that 01 at 0'2 . 2 O Reject Ho' We can conclude that 0'12 i 0'2 . 0 Do not reject HO' We can conclude that 012 :t 022. (b) Repeat the test using the critical value approach. Find the value of the test statistic. |:| State the critical values for the rejection rule. {Round your answers to two decimal places. If you are only using one tail, enter NONE For the unused tail.) State your conclusion . O Reject HO' We cannot conclude that 012 i 022. 2 2 0 Do not reject H0. We cannot conclude that 01 at 0'2 . O Reject H". We can conclude that 0'12 t 0,2

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