Please help!

Equations & Constants 1 cm = 1 mL Trig Functions: 60 s = 1 min 2.54 cm = 1 inch Acceleration due to Gravity: sin 0 = opposite hypotenuse 60 min = 1 hr ]' 12 inches = 1 ft ( dy = -g = -9.81 m/s2 cos 0 = adjacent 3 ft = 1 yrd tan 0 = opposite adjacent Kinematics Displacement: Constant Acceleration in x: Constant Acceleration in y: Ax = xf - Xi Vxf = Vxi + art Vyf = Vyi + ayt Constant Velocity: Ax = 2(Vxi + Vaf)t Ay = 2(vyi + Uuf)t 0 = Vi = Uf Ax = Unit + jaxt2 Ay = Unit + Hayt2 Ax = vt U2 = Uzi + 2axAx but = Uni + 2ay Ay Forces Newton's Laws: Weight: Friction: CF =0 -a=0 F, = mg S fs S Us FN EF = ma Centripetal Acceleration: ( fk = HKFN Fzon1 = -Flon2 ac = 02 / R Hooke's Law: F, = -k(AT) Energy Types of Energy: KE = :mv2 Work: PE, = mgh Work Energy Theorems: W = F . Ax PE, = \\k(4x)2 EW tot = AKE (W = Fx cose) Etot = KE + PE, + PE, EW = -APE AEtot = AKE + APE, + APE, EWnc = Etot P = AEtot/ At 1. (4 pts) A vollyball player hits a ball vertically upwards with an initial velocity of 7.0 5. (6 pts) Fill out the plots below for position, velocity, and acceleration. From m/s. What is the maximum height that the ball attains? t = 0 to t = 5s, a car moving in the negative direction slows down and comes to a stop. For 3 seconds the car does not move. Then, from t = 8s to t = 10s the car goes in reverse (in the positive direction), at a steady pace. Finally, from t = 10s to t = 12s the driver continues moving in the positive direction with increasing speed. [HINT: at any given interval, you will need to pick a curve that looks like one of the seven curves below, though of course, you might have to cross the horizontal axis.| 8s 12s x 2. (4 pts) An object traveling with an initial velocity of 4 m/s slows down to rest in 20 m. What is its acceleration during this slow down period? v 3. (4 pts) An object traveling with an initial velocity of 4 m/s speeds up with an acceleration a of 10 m/$2. How far away will it be in 2 s? AZE 4. (4 pts) What is the final velocity of a ball that is thrown straight down with an initial velocity of 15.0 m/s from a height of 10 m? KUL'D