Please help me answer the following question. Thank you

Question 5

Critical Values of F For a particular combination of momentor and denominator degrees of freedom, entry represents the critical values of / comespending to the cumulative probability (I - o) and a specified upper-tail and (at. Com dave Probabilities = 0.14 parTilAnn - 185 Denondnat or 12 15 1 2:30 DO 251.10 232.20 243.30 161,40 190.50 215.70 234.60 230.20 236.80 238.90 24050 241.90 343190 1947 19.50 18.51 19 1 19. 16 19.25 19.10 19.13 1941 1941 4.74 10. 13 955 9.12 600 7.71 LTT 6.61 5.7 J.BI 174 4 76 4.15 5.09 5,14 4.51 3.A 3. 30 3.30 SET 3.97 3.79 EL'E 3.57 3.51 3.01 2.97 5.5 1.501 139 135 1.15 2.75 2.71 5.32 407 4.36 1 17 LIN 114 5,13 2.TO 2.58 24 JOT 298 2.09 290 285 2.79 2.61 2.57 2.45 161 4.84 HE'E 2.75 2.62 14 2.51 2.47 2. 18 J.26 3.11 2.30 2.35 2.21 4.75 1.49 291 2.85 2.41 1.41 3.01 2. 77 171 267 2 60 INE 203 265 2.60 2.53 231 2. 18 4,60 J.74 2.76 2.20 2. 16 1.54 171 2.61 2.15 2.06 254 2.19 2.01 2.59 4,49 2.19 2.15 ort 2.06 2.0 149 245 2.38 4,45 1.20 161 1.19 2.11 1.06 J.16 3.17 2.51 218 2.31 1.16 2.11 207 2.03 1.95 1.53 144 2.48 142 1.13 3.71 139 135 2.28 2.04 149 2.87 212 201 1.56 1.32 2.41 217 2.25 2.10 2108 1AT 2.40 134 2.15 1.07 191 146 2.21 2.01 1.89 1.30 217 3.30 1.01 2.01 1 91 1.56 4.25 3.80 210 215 2.18 20 1.98 1.59 4,36 1/40 2.16 101 1.06 4.24 2.76 1.90 1.85 1.80 4.23 2.74 2.47 2.39 2.32 127 2.15 4.21 1.73 1.17 2.31 1.90 1.87 2.71 324 219 2.12 1.91 1,20 2.10 1.90 1.31 1.75 4. 15 1.33 1.70 321 216 1.89 1.74 2.41 2.21 4, IT 1.61 212 108 200 1.79 1.64 4.08 204 1.90 1 90 1.75 1.70 1.65 1.53 1,15 2.76 2.53 2.37 1.17 2. 10 4,00 1.61 1.59 1.30 2.45 117 196 1.83 210 1.79 1.32 2.37 2.21 201 1.01 1.M4 14 Denominator.FE IFI IIT GIT IFE FIT OCI IFT 171 IFE FIT LET IIT LIT WE SIT D'E LEF BIT ISE 2.75 ET'E FET WE SIT HET LIFE IFE HE HE SIT IFE LIFE IST LIE ET'E art ID'E 95 HE 109 91 150 HE OF'E ECT FI IFE LEE IT ME LL'E LET art NT. IF'E LIT Or's $5 9 II CIT WE 01 HIT LOT 169 STE IFE LET PIT 45 4 SET CI'S 192 #59 CTY AL'Z TITI LITI 0151 IFGE GENE 9E GE EETHE SC GE LITE 15 HE EI Cumulative Probabilities = 0.715Com da live Probabilities =0.19 Upper-Tall Ann = ill Numerator dhi Denominator, 1 15 4052.00 4949.50 5403.06 563500 5,764.60 5,854010 5,918,00 5.902.00 6 10600 6 157.00 19 15 3.12 28. TI 28.24 27.91 17.67 26 50 26.13 21.20 15.52 15.21 14.98 14.37 STEI 1 3.46 16.26 13.27 12/06 11 19 1097 10.67 10.46 13,73 10492 8.47 8.36 7.72 7.56 7.31 7.14 12.25 9.85 8.45 7.46 7.19 6.72 647 6007 5.91 11.26 7.59 6.63 6.37 5.91 5.67 5.52 3.12 10. 50 4.57 4 40 10,04 7.5 3.64 5.39 5.30 5.06 4.71 1.56 LAI 4.17 4:0O 9,65 7.21 6.13 5.07 4.74 4. 10 9,33 6,93 4,82 4.50 3.86 3. TH 354 3.43 3.36 4,07 6, 70 S.T. J.M J.H 6.51 5.56 5 01 4.46 1.80 3.51 14 167 1,53 6.21 4.44 4.30 3.41 3.36 2 81 2.73 8,40 4.67 4. 10 3.91 2.79 1.25 4,01 3.71 191 3.31 2.73 257 5.91 4.17 J. 77 J.30 3.15 2.5 8, 10 J.87 3, 70 3.56 117 2.50 2.61 4 17 3.51 J.17 5.72 3,76 1.59 167 2.50 2.40 1.71 121 3.78 1.36 7.82 5.61 1.40 1.50 1.17 2.89 231 231 7.77 2.70 14 217 7.72 1.82 3.59 3,42 2.81 2.30 203 7.68 5.49 1. TH 3.56 3.39 3.36 1.401 2.78 2.61 247 2.30 2.10 7.64 1.75 J.36 112 2.73 2.35 2.26 2.17 206 7.60 5.41 LOI 3.50 1.31 1.00 1.87 2.71 241 2.H 7.56 5.39 1.70 J.47 3.30 2.70 2.59 247 2.30 2.21 2.11 201 7.31 4.31 151 1.29 3. 12 1.80 1.66 3.37 2.11 7,06 3.12 2.12 161 250 2.35 2.20 2.12 101 130 1.91 1,17 1.79 2.19 1.91 4.60 112 2.80 2.12 INenoninator\fHomework: Module 10- One-way ANOVA Save Score: 0 of 1 pt 5 of 14 (11 complete) HW Score: 59.1%, 8.27 of 14 pts X 13. 1.14 Question Help An experiment has a single factor with three groups and four values in each group. In determining the among-group variation, there are 2 degrees of freedom. In determining the within-group variation, there are 9 degrees of freedom. In determining the total variation, there are 11 degrees of freedom. Also, note that SSA = 48, SSW = 72, SST = 120, MSA =24, MSW = 8, and FSTAT = 3. Complete parts (a) through (d). Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. a. Construct the ANOVA summary table and fill in all values in the table. Degrees of Sum of Mean Square Source Freedom Squares (Variance) F Among groups Within groups Total (Simplify your answers.)