Please help me do numbers 33-60 in multiples of 3. So like by 3's

In Exercises 33-38, find the zeros of the function algebraically. 33. f(x) = x2+ 2x - 8 34. f(x) = 3x2+ 4x - 4 35. f (x) = 9x2 - 3x - 2 36. f(x) = x3 - 25x 37. f (x) = 3x3 - x2 - 2x 38. f(x) = 5x3 - 5x2 - 10x In Exercises 39-42, state the degree and list the zeros of the polynomia function. State the multiplicity of each zero and whether the graph crosses the x-axis at the corresponding x-intercept. Then sketch the graph of the polynomial function by hand. 39. f (x ) = x(x - 3) 2 40. f ( x ) = - x3( x - 2 ) 30 30 41. f (x) = (x - 1)3(x + 2)2 42. f (x) = 7(x - 3)2 (x+ 5) 4 In Exercises 43-48, graph the function in a viewing window that shows all of its x-intercepts and approximate all of its zeros. 43. f ( x ) = 2x3 + 3x2 - 7x - 6 44. f (x) =-x3 + 3x2 + 7x - 2 45. f(x) = x3 +2x2 -4x - 7 46. f(x) = -x4- 3x3 + 7x2 + 2x + 8 47. f (x) = 14+ 3x3 - 9x2 + 2x + 3 48. f (x) = 2x5 - 11x4 + 4x3 + 47x2 - 42x - 8 In Exercises 49-52, find the zeros of the function algebraically or graphically. 49. f(x ) = x3 - 36x 50. f(x) = x3+ 2x2 - 109x- 110 51. f(x) = x3 - 7x2 - 49x + 55 52. f(x ) = x3 - 4x2 - 44x + 96 In Exercises 53-56, using only algebra, find a cubic function with the given zeros. Support by graphing your answer. 53. 3, -4, 6 54. -2, 3, -5 55. V3, - V3, 4 56. 1, 1 + V2, 1 - V2 57. Use cubic regression to fit a curve through the four points given in the table. x - 3 y 22 25 12 58. Use cubic regression to fit a curve through the four points given in the table. x - 2 4 7 2 5 9 26 59. Use quartic regression to fit a curve through the five points given in the table. x 3 4 5 6 - 4 -11 8 60. Use quartic regression to fit a curve through the five points given in the table. x 0 4 5 7 13 -21 -19 -12 8 3