please help me in answer by using matlab only!

Bisection Method: Example 5.3 Computational Methods in Engineering CLOSED METHODS Solve Problem 5.1 by using bisection method. 38 20.146843x) 40 . 667.38 CX f(x)= (1-e-014 Step 1: x = 12 x, = 16 40 f(c) 4 X, Step 2: x+xu 12 +16 = 14 2 2 real estimated x100 (%) x,real . 6. E, (14.7802-14 *100 (%) = %5.279 14.7802 Step 3: f(x).f(x)=f(12). f (14) 6.067(1.569) = 9.517>0 => x = x, _ (Step 2) X, 14+16 = 15 2 2.ROOT FINDING - 11 Example 5.3 new x Computational Methods in Engineering Bisection Method: previous 15-141 X100 (%) => a = x100 (%)=%6.667 15 11 new .x, Et 14.7802-15 4x100 %= %1.487 14.7802 (Step 3) f(x): f(x) = f(14) f(15) 1.569(-0.425) =-0.666