Please help me on my homework! Please show all your work and highlight the answer! Thanks :)

1. A company records the commute distances (distance traveled from home to work) of all of its 40 employees. By mistake, the largest commute distance is recorded as 165 miles instead of 16.5 miles. By how many miles does this mistake change the median of the commute distances? A. 2.32 miles B. 4 01 miles C. 0 mile D. 3.71 miles 2. Cliff is playing a four person card game with friends. He thinks he is skilled and has a better chance of winning than random chance, so he estimates that his probability of winning an individual card game is 0.4. Assuming that each card game played is independent of the other card games, Cliff announces that his probability of winning both card games is 0.8. What is the best assessment of this statement? A. This is a correct probability calculation because Cliff just adds the probability of winning cach card game. B. This is an incorrect probability calculation because Cliff should have multiplied the probability of winning each card game. C. This is an incorrect probability calculation because Cliff should have used the formula P(A or B) = P(A) + P(B) - P(A and B). D. This is an incorrect probability calculation because Cliff did not use the normal distribution.3. A researcher studying how monkeys remember is interested in examining the distribution of the score on a standard memory task. The researcher wants to produce a boxplot to examine this distribution. Below are summary statistics from the memory task. What values should the researcher use to determine if a particular score is a potential outlier in the boxplot? min Q1 median Q3 max mean ad n 26 37 46 49.8 65 44.4 8.4 50 A. 37.0 and 49.8 B. 17.8 and 69.0 C. 36.0 and 52.8 D. 26.0 and 50.0 E. 19.2 and 69.9 4. A producer of a certain type of electronic component ships to suppliers in lots of twenty (i.e., each lot contains 20 electronic components). Suppose that 60% of all such lots con- tain one defective component, 30% contain two defective components, and 10% contain three defective components. A lot is picked at random, two components from the lot are randomly selected and tested. (a) Given that the lot contains one defective component, what is the conditional prob- ability that exactly one of the two tested components is defective? (b) Given that exactly one of the two tested components is defective, what is the con- ditional probability that the lot contains one defective component? 5. Suppose that the area under a standard normal curve between & and 2.80 is 0.6. What is the value of z? Page 2Normal probability table Second decimal place of Z 0.09 0.08 0.07 0.05 0.04 0.03 0.02 0.01 0.00 0.0002 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 D.0003 0.0003 0.0003 -3.4 10003 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0005 0.0005 0.0005 -3.3 0.0006 0.0905 0.0006 0.0005 0.0006 0.0006 0.0006 9.0005 0.0007 -3.2 0.0007 0.0007 1.0008 0.0008 0.0008 0.0008 0.0009 0.0009 0.0009 0.0010 -3.1 0.0010 0.0010 0.0011 0.0011 0.0011 0.0012 0.0012 D.0013 0.0013 0.0013 3.0 0.0014 0.0014 0.0015 0.0015 0.0016 0.0016 0.0017 0.0018 0.0018 D.0019 -2.9 0.0019 0.0021 020021 0.0021 0.0022 0.1023 0.0023 0.0024 0.0025 0.0026 2.8 D.0026 0.0027 0.0028 0.0029 0.0030 0.0031 0.0093 0.00.35 0.0034 0.0035 -2.7 0.0036 0.0047 0.0038 0.0039 0.0040 0.0041 0.0043 D.0044 0.0045 0.0047 -2.6 0.0048 0.0048 0.0051 0.0052 0.0054 0.0065 0.0057 0.0059 0.0060 D.0062 -2.5 D.006-4 0.0056 0,0068 0.0069 0.0071 0.0073 0.0075 0.0075 0.0080 0.0082 -2.4 0.0084 0.0087 0.0089 0.0091 0.0094 0.0096 0.0099 0.0102 0.0104 0.0107 -2.3 10110 0.0113 0.0116 0.0119 0.0132 0.0125 0.0129 0.0132 0.0136 0.0139 -2.2 0.0143 0.0146 0.0154 0.0158 0.0162 0.0166 0.0170 0.0174 D.0179 -2.1 10183 0.0185 10192 0.0197 0.0202 0.1207 0.0212 0.0217 0.0222 0.0225 -2.0 0.0233 0.0239 0.0244 0.1250 0.0256 0.0262 0.0268 0.0274 0.0281 D.0287 -1.9 0.0294 0.0301 0.0307 0.0414 0.0322 0.04:29 0.0336 D.0-4-4 0.0351 D.0359 -1.8 0.0367 0.0375 0.0384 0.0392 0.0401 0.0409 0.0418 0.0427 0.0436 0.0446 -1.7 0.0465 0.0465 0.0476 0.0485 0.0496 0.0605 0.0516 0.0526 0.0537 D.05-48 -1.6 0.0559 0.0471 0.0582 0.0594 0.0606 0.0618 0.0630 0.06-43 0.0655 D.0868 1.5 0.0694 INCITING 0.0721 0.0735 0.0749 11.0784 0.0778 1.0794 DOBOS -1.4 0.0823 0.0838 0.0853 0.0850 0.0885 0.0901 0.0918 0.0934 0.0951 0.0968 -1.3 0.0985 0.1003 0.1020 0.1038 0.1056 0.1075 0.1093 0.1112 0.1131 0.1151 -1.2 01170 0.1190 0.1210 0.1230 0.1251 0.1271 0.1292 0.1314 0.1335 0.1357 -1. 1 0.1379 0.1401 0.1423 0.1446 0.1469 0.1492 0.1515 0.1539 0.1562 0.1587 -1.0 0.1611 0.1635 0.1660 0.1085 0.1711 0.17:36 0.1762 0.1789 0.1814 0.1841 0. 1867 0.1894 0.1932 0.1949 0.1977 0.2005 0.2093 0.2061 0.2090 0.2119 -0.8 1.2148 0.2177 0.2206 0.2236 0.2266 0.2296 0.2327 0.2358 0.2389 0.2420 -0.7 0.2451 0.2483 0.2514 0.2546 0.2578 0.2611 0.2643 0.2676 0.2709 0.2743 -0,6 0.2776 0.2810 0.2843 0.2877 0.2912 0.2946 0.2981 0.3015 0.3050 0.3085 -0.5 0.3121 0.2156 0.3192 0.32:28 0.3264 0.3:300 0.3236 0.1372 0.3409 0.3446 -0.4 0.3483 0.3520 0.3557 0.3594 0.3632 0.36 69 0.3707 0.3745 0.3763 0.3821 0.3859 0.3297 0.3936 0.3974 0.4013 0.4062 0.4090 0.4129 0.4108 0.4207 -0.2 0.4247 0.4286 0.4325 0.4364 10.4404 0.4443 0.4483 0 0.4522 0.4562 0.4602 -0.1 0.4641 0.4721 0.4761 0.4501 0.4840 0.4880 D.4920 0.4960 D.5000 -0.0 "For Z