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Please help me solve the moles of hydrogen gas present in the mixture of the vapor pressure of water at 298K is 23.8mmHg. - A

Please help me solve the moles of hydrogen gas present in the mixture of the vapor pressure of water at 298K is 23.8mmHg. image text in transcribed
- A chem 202 student collects 35,0mL of hydrogen gas over water at 298k. - The total pressure of the mixture of gases is 750mmHy - Calculate the moles of hydrogen gas present in the mixture if the vapor pressure of water at 898k is 23.8mmHg Ptotal=PH2O+Pgas750mmHg760mmHt1atm=0,9868421053moles=mass=0.987atmPtotal=0.987atm V1=35.0mLT1=298k moles of hydrajn gas? P2=23.8mmHt=0.987atm

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