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please help. Suppose that the heights of adult men in the United States are normally distributed with a mean of 69 inches and a standard

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please help.

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Suppose that the heights of adult men in the United States are normally distributed with a mean of 69 inches and a standard deviation of 3 inches. What proportion of the adult men in the United States are more than 6 feet tall? (Hint: 6 feet = 72 inches.) Round your answer to at least four decimal places. X 5 2

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