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Please help with explanation! Given that the graph at Hi) passes through the point (9, 3) and that the slope of its tangent line at
Please help with explanation!
Given that the graph at Hi") passes through the point (9, 3) and that the slope of its tangent line at (3: x\" is 33' + 6, what is H3]? [3 A particle moves on a straight line and has acceleration a (t) = 18t + 16. Its position at time t = 0 is s(0) = 15 and its velocity at time t = 0 is v(0) = 1. What is its position at time t = 9Step by Step Solution
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