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Please help with parts h-j ONLY show all steps to get a good rating. (b) (C) (d) (f) (g) (h) Eumh point at. some location
Please help with parts h-j ONLY show all steps to get a good rating.
(b) (C) (d) (f) (g) (h) Eumh\" point at. some location P on the zaxis at. height. a > f]? (ii) What must. the value of Emmwtz = 0) be at the center of the washer? Explain your reasoning. What is the total charge (gum... of the washer"? Express your answer in terms of a, h, and (2. [Note: [or practice, this part should be done via an integration (Jammy = f (1Q. Start by writing down the charge (M) of a very thin ring of radius r and width ch- as (lQ : U.'l,.,;ng. where fin-"g is the area. of the thin ring. Look at. the Calculus Review il-laterials on Canvas ityou need help with this. Your result. should depend on (r. and then you can integrate as a function of 1' over the range b g r 5 t' to get Qwaihr. l Suppose that. 0 : '2 x 10'\" (7/1112, t) : (1.01 in (1 cm), and c : 0.0-4 III (11 cm). Find (June-fie? Hos: 9.4 x 10 9 C] 'What would you expect Ewshw to be as the point. P moves a very great distance from the ring up the z-axis? (i.e. far enough that. from the point P you can't discern the washer-3s structure - just. that it is a blob of charge Quay\")? Of course. it goes to zero, but what. would you expect. the the zdependence of Emma," as it approaches 0'.' Explain your reasoning. Now that you have some idea of what. to expect. use the result given for a thin ring Ez',.mg to compute the elect rie field E,,.m,;m,. (as a vector) at a distance 5 along the zsaxis. Do not. plug in numbers for (I, h, and (I in this step. Check that. you get. the expected result when 2 = 0. Don't worry about checking the largevz result just yet. Wyetll try that. for a later part. [Miter this part. requires integration. Start by using the Eating result above to write down the field (lEz of a verv thin ring; of radius r and width (11' and do an integral E2 : f (1E2. How will you write Qm'g for that. ring in terms of (I. r, and (tr? ( Hint: you did this already in part 03)) Once. you have (17E; you can integrate over 7' in the range in the range I) g r g r to get. your answeraT Suppose that again or = 2 x 10\"" 0/1112, t) = 0.01 1111 and e = 0.04 11]. Find the magnitude of Ewan\"... at. height. 2 : 5 cm. Mus: 2.26 x 10'1 N/C] What. happens when you let. I) A it? (This corresponds to the field 1511in of a charged disk of radius c.) [Note you can check this answer in the Knight term] What happens to the answer from part (g) when you next let. e > too? (This limit. corresponds to an infinite uniformly charged plane. lts field can also he calculated using Gauss's law. so the answer to this part. is hiding in the prelecture for Unit 4.) Now instead1 let .3 > 0 in the answer to part (g). What result do you get? This is why we say that. we can usefully use the idealized model of' an infinite charged sheet as a stand-in for a finite-sized charged sheet. if' we are close to the surface of the sheet. (i) Based on the analysis you did for part (d), what do you expect to happen to the answer from part (g) when you let z become very large, i.e., when z > c? Briefly justify your answer. (j) Make plots of the results for the magnitudes of Ewasher and Edisk as a function of z that you computed in parts (e) and (g). Again use the values o = 2 x 10-6 C/m', b = 0.01 m, and c = 0.04 m. Pick a convenient plotting range, such as 0 0 (Le, a has units C / m2). The goal of this problem is to calculate the electric eld along the axis of symmetry of the washer, which corresponds to the z axis of the coordinate system. as shown, while looking at various limiting cases of interest. You should use as your starting point the Iicld along the axis of a thin ring of radius R and total charge Qmm. which was discussed in lecture: Enemy = kQTmy (z? + \"Rag/'2 (I)Step by Step Solution
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