Please I need help answering the following,

A)

(1 point) IQ scores have a mean of 101 and a standard deviation of 14. Ted has an IQ of 106. (a) What is the difference between Ted's IQ and the mean? Answer: (b) Convert Ted's IQ score to a z-score (round to 2 decimal places) Answer:(1 point) The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same age have mean height 69.3 inches with standard deviation 2.8 inches. (a) What is the z-score for a woman 77 inches tall? z-score = (b) What is the z-score for a man 61 inches tall? z-score = (1 point) (a) For a normal distribution, find the z-score that cuts off the bottom 58.51 % of all the z-scores. Round to 2 decimal places after me decimal point. (1 point) The distribution of heights of adult men in the U.S. is approximately normal with mean 69 inches and standard deviation 2.5 inches. Use what you know about a normal distribution and the Empirical rule to answer the following. NOTE: If your answer is a percent, such as 25 percent, enter: "25 PERCENT" (without the quotes). If your answer is in inches, such as 10 inches, enter: "10 INCHES" (without the quotes and with a space between the number and the INCHES). If your answer is an interval, such as 14 to 15 inches, then enter: "14 TO 15 INCHES" (without the quotes). Do not use extra zeros and do not include a decimal point unless your answer is not a whole number. Your answer must be entered in the correct format. (a) About what percent of men are taller than 74? Answer: 2.28 PERCENT (b) About what percent of men are between 69 and 74 inches? Answer: 47.5 PERCENT (0) Between what approximate heights do the middle 95 percent of men fall? Answer: 64.1 TO 73.9 INCHES