Please I need the answer to C

A social media survey found that 70% of parents are "friends" with their children on a certain online networking site. A random sample of 160 parents was selected. Complete pans a through d below. a. Calculate the standard error of the proportion. up = 0.0362 (Round to four decimal places as needed.) b. What is the probability that 117 or more parents from this sample are "friends" with their children on this online networking site? P(117 or more parents from this sample are "friends' with their children) = 0.1940 (Round to four decimal places as needed.) c. What is the probability that between 112 and 119 parents from this sample are "friends" with their children on this online networking site? P(Between 112 and 1 19 parents from this sample are "friends" with their children) = (Round to four decimal places as needed.)