To determine a target audience for a new email package, a computer company surveyed a large random sample of potential customers, asking each whether he/she uses email on a regular basis. (The company considered "a regular basis" to be at least three times a week.) The data, as summarized in the contingency table below, were classified according to two variables: the age of the respondent ("under 18", "18-35", "36-54", "55+") and reqularity of email use ("on a regular basis" or "not on a regular basis"). Each cell of the table contains three numbers: the first number is the observed cell frequency (fo); the second number is the expected cell frequency (f.) under the assumption that there is no dependence between age and regularity of email use and the third number is the following value. (fo-fE) (observed cell frequency-Expected cell frequency) fE Expected cell frequency The numbers labeled "Total" are totals for observed frequency. Part 1 values to three Fill in the missing values in the contingency table. Round your expected frequencies to two or more decimal places, and round your or more decimal places. Age (in years) 18-35 36-54 55+ Total Under 18 123 104 45 116 On a regular 111.74 123.77 388 basis 0.536 0.488 Regularity of 174 184 51 203 O CHI-SQUARE TESTS, INFERENCES FOR REGRESSION, AND ANOVA Emmanuel V Chi-square test of independence Part 1 values to three Fill in the missing values in the contingency table. Round your expected frequencies to two or more decimal places, and round your fE or more decimal places. Age (in years) Under 18 18-35 36-54 55+ Total 123 104 45 116 On a regular 111.74 123.77 388 basis 0.536 0.488 Regularity of email use 174 184 51 203 Not on a 176.26 195.23 612 regular basis 0.34 0.309 288 96 319 1000 Total 297 Part 2 Answer the following to summarize the test of the hypothesis that there is no dependence between age and regularity of email use. For your test, use the 0.10 level of significance. (a) Determine the type of test statistic to use. Explanation Check 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy | Accessibility 0 pe here to search www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IBGBIH_OB3uhhqwxlXoS5SIQhuX6YjFjUgDFNRi1XW55GbFcQGhku9Q7sgecvvswElx4pwmofvh3mof Zpl5QbHHZ0Gb1dq?1oBw7QYjlbavbSPXtx-YCjsh_7mMm O CHI-SQUARE TESTS, INFERENCES FOR REGRESSION, AND ANOVA Chi-square test of independence Emmanuel V 176.26 195.23 612 regular basis 0.34 0.309 Total 297 288 96 319 1000 Part 2 Answer the following to summarize the test of the hypothesis that there is no dependence between age and regularity of email use. For your test, use the 0.10 level of significance. Aa (a) Determine the type of test statistic to use. Type of test statistic: (Choose one) (b) Find the value of the test statistic. (Round to two or more decimal places.) (c) Find the critical value for a test at the 0.10 level of significance. (Round to two or more decimal places.) (d) Can we reject the hypothesis that there is no dependence between age and regularity of email use? Use the 0.10 level of significance. O Yes O No Explanation Check 2020 McGraw-Hill Education. All Rights Reserved. Tems of Use Privacy I Accessibility 0 O Type here to search II