please make the answers clear

1. [-11 Points] DETAILS SERCP7 19.AE.02. Example 19.2 A Proton Moving in a Magnetic Field Goal Calculate the magnetic force and acceleration when a particle moves at an angle other than ninety degrees to the eld. Problem A proton moves at 7.92 x 106 m/s along the x axis. It enters a region in which there is a magnetic field of magnitude 2.90 T, directed at an angle of 60.U with the x axis and lying in the xyplane (Fig 19.8). (a) Find the initial magnitude and direction of the magnetic force on the proton. (b) Calculate the proton's initial acceleration. Strategy Finding the magnitude and direction of the magnetic force requires substituting values into the equation for magnetic force, Equation 19.1, and using the righthand rule. Applying Newton's second law solves part Figure 19.8 The magnetic force I? on a proton is (b)- in the positive zdirection when '7 and 1? lie in the xyplane. Solution (a) Find the magnitude and direction of the magnetic force on the proton. Substitute v : 7.92 x 105 m/s, the magnetic eld F = qu sin 9 strength B : 2.90 T, the angle, and the charge of a = -19 5 . proton into Equation 19-1. 20)[1'60 x 10 C)(7.92 x 10 m/s}(2.90 T)(sm Apply the righthand rule number 1 to find the initial Point the fingers of the right hand in the xdirection direction 0f the magnetic force. (the direction of i3), and then curl them towards i. The thumb points |-- direction -- V I . (b) Calculate the proton's initial acceleration. Substitute the force and the mass of a proton into me = F 1, (1.67 x 10-27 kg)a = F I Newton 5 second law. a = E m/sz Remarks The initial acceleration is also in the positive zdirection. Because the direction of 9' changes, however, the subsequent direction of the magnetic force also changes. In applying righthand rule number 1 to find the direction, it was important to take into consideration the charge. A negatively charged particle accelerates in the opposite direction. Hints: Getting Started | I'm Stuck Calculate the acceleration of an electron that moves through the same magnetic eld as in Example 19.2, as the same velocity as the proton. The mass of an electron is 9.11 x 10'31 kg. elect... : S we in the 2. [-11 Points] SERCP7194P.003. Find the direction of the magnetic field acting on the positively charged particle moving in the various situations shown in Figure P193, if the direction of the magnetic force acting on it is as indicated. F 15 V @i'louli m (m 10 Figure P193 (a) (a) (c) 3. [-l1 Points] DETAILS SERCF719.P.004. Determine the initial direction of the deflection of charged particles as they enter the magnetic elds, as shown in Figure Fig.4. Figure P19.4 Figure (a) Figure (b) Figure in) Figure (d) 4. [-/1 Points] DETAILS SERCP7 19.P.008. An electron is accelerated through 2400 V from rest and then enters a region where there is a uniform 1.40 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? (a) maximum IN (b) minimum. [-11 Points] SERCF7 19.P.004. Determine the initial direction of the deflection of charged particles as they enter the magnetic elds, as shown in Figure P19.4. (a) c:_..__ n. n A Figure (ti up 3 Figure ((1 down Figure (d l I in the right i 1 lo the left 3 i into the page Sh nut of the page no deection Aeeeeefeeeeeeeeeee 2. [-11 Points] SERCP719.P.003. Find the direction of the magnetic field acting on the positively charged particle moving in the various situations shown in Figure P193, if the direction of the magnetic force acting on it is as indicated. F r' i? 4 V Vioull (a) (h) (c) \"\"m' \"t9.3 (a (b out of the page (C to the left to the right u pward ' downward FM.) 0 into the page A current I = 15 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.13 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes. T --Select--.A current I = - 4 :- ing the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.13 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes. ---Select--- +x direction -x direction Show N +y direction y direction +z direction Submit Answe -z directionIn Figure. P.19.2, assume that in each case the velocity vector shown is replaced with a wire carrying a current in the direction of the velocity vector. For each case, find the direction of the magnetic force acting on the wire. (a) ---Select--. v (b)"---Select- c) ---Select--- (d) ---Select--- (e) ---Select--. (f) ---Select--- (d) -B (1) Figure P19.2wowthat in each case the velocity vector shown is replaced with a wire carrying a current in the direction of the velocity vector. For each case, find the direction of the magnetic force acting on the wire. (a V ---Select--- downward out of the page upward to the left into the page to the right B ( 2) ( b ) .A. (1) Figure P19.2The two wires shown in Figure P1938 carry currents at 5.00 A in apposite directions and are separated by 10.0 cm. Find the direction and magnitude df the net magnetic eld at the following locations. am A 5 00 a *3 PI rum'gu um um rm lll ll(m-{ Figure P1938 (a) at a point E (b) at point P1, 100 cm to the right of the wire on the right :T (c) at point P2, 20.0 cm to the left of the wire on the left ET The two wires shown in Figure P19.38 carry currents of 5.00 A in opposite directions and are separated by 10.0 cm. Find the direction and magnitude of the net magnetic field at the following locations. 5.00 A 5.00 A -20.0 cm- *-10.0 cm- -10.0 cm- Figure P19.38 (a) at a point midway hatwon the wires V ---Select--- (b) at point F to the right of the wire on the right out of the page c) at point F downward f the wire on the left to the left into the page upward