please make the answers clear for each question

Consider the combination of capacitors in Figure P16.34 (C1 = 20.0 AUF, C2 = 3.00 AUF). 36 V 4.0 HF C2 8.0 HF Figure P16.34 (a) What is the equivalent capacitance of the group? AUF (b) Determine the charge on each capacitor. the 4.00 AUF capacitor AUC capacitor C2 AuC capacitor C1 AUC the 8.00 AUF capacitor AHC9. [-/1 Points] DETAILS SERCP7 16.P.033. Four capacitors are connected as shown in Figure P16.33 (C = 16.0 AUF). C 3.00 UF 20.0 HF 6.00 HF Figure P16.33 (a) Find the equivalent capacitance between points a and b. AUF (b) Calculate the charge on each capacitor if a 12.0 V battery is connected across points a and b. the 20.0 AUF capacitor AuC the 6.00 AUF capacitor AUC the 3.00 AUF capacitor AuC capacitor C AUC8. [-/1 Points] DETAILS SERCP7 16.P.031. 4.00 UF 3.00 ALF 2.00 UF 12.0 V Figure P16.31 (a) Find the equivalent capacitance of the capacitors in Figure P16.31. AUF (b) Find the charge on each capacitor and the potential difference across it. Charges AUC (2.0 AUF capacitor) ANC (3.0 AUF capacitor) AUC (4.0 AUF capacitor) Potential Differences V (2.0 AUF capacitor) V (3.0 AUF capacitor) V (4.0 AUF capacitor)Three capacitors, C1 = 3.00 AUF, C2 = 6.00 AUF, and C3 = 9.00 AuF, are connected together. Find the effective capacitance of the group for the following situations. (a) if they are all in parallel AUF (b) if they are all in series AUFA series circuit consists of a 0.054 AUF capacitor, a 0.090 AUF capacitor, and a 385 V battery. Find the charge for the following situations. (a) on each of the capacitors AUC (0.054 AUF capacitor) AUC (0.090 AUF capacitor) (b) on each of the capacitors if they are reconnected in parallel across the battery AUC (0.054 AUF capacitor) AUC (0.090 AUF capacitor)An airfi||ed capacitor consists of two parallel plates, each with an area of 760 cm2, separated by a distance of 2.10 mm. If a 18.0 V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates 2 kvxm (b) the capacitance SW (C) the charge on each plate Eve 4. [-/1 Points] DETAILS SERCP7 16.P.011. (a) Find the electric potential 2.00 cm from a proton. V (b) What is the electric potential difference between two points that are 2.00 cm and 5.00 cm from a proton?An ion accelerated through a potential difference of 60.00 V has its potential energy decreased by potential energy of 1.92 x 10'17 J. Calculate the charge on the ion. C a A potential difference of 80 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative relative to the outer surface. How much work is required to eject a positive sodium ion (Na+) from the interior of the cell? SJ 1. [-!1 Points] DETAILS SERCP716.AE.04. Example 16.4 Flndlng the Electric Potentlal Goal Calculate the electric potential due to a collection of point charges. Problem A 4.90 |J (3 point charge is at the (0:400) P origin, and a point charge qz = -1.90 0C is on the x-axis at (3.00, 0} m, as in Figure 16.8. (a) If the electric potential is taken to be zero at infinityr find the total electric potential due to these charges at point Pwith coordinates (0, 4.00) m. (b) How much work is required to bring a (3.00, 0) third point charge of 4.00 [.16 from infinity to P? Figure 16.8 The electric potential at point P due to the point charges ql and 02 is the algebraic sum of the potentials due to the individual charges. Strategy {a} The electric potential at P due to each charge can be calculated from V = keqfr. The total electric potential at P is the sum of these two numbers. (b) Use the work-energy theorem, together with Equation 16.5. recalling that the potential at infinity is taken to be zero. Solution I (a) Find the electric potential at point P. Calculate the electric potential at P due to the 4.90 m (8 99 10.]N - 1112) (4.9 x 105 C) . x ' 1! = 1-.._ = . pC charge. I 1-] C2 4.00 111 UL = 1.10 x 104 v Find the electric potential at P due to the -1.90 uC r\" .1 N - 1n2 1.9 x 106 C- V = '. = 8.99x10' . . charge. ' ' r] C13 0.00 In vL = -3.42 x 103 v Sum the two numbers to find the total electric VP 2 V1 + 1/2 = 1.10 x 104 V + (.142 x 103 V) potential at P. VP = \\:| V (b) Find the work needed to bring the 4.00 0C charge from infinity to P. Apply the work-energy theoremr with Equation U" = $13.13. = rmi' = 9131-}, VI 16.5. w = (4.00 x 10'6 c)(vp - 0) W=EJ Hints: Getting Started | I'm Stuck Suppose a charge of -1.90 uC is at the origin and a charge of 3.10 pC is at the point (0, 3.00} m. (a) Find the electric potential at (4.00, 0} m, assuming the electric potential is zero at innity. (b) Find the work necessary to bring a 4.00 pC charge from infinity to the point 400,0 m. W: J